∫ 6x^2-17x+12 eching

$$\int 6 x ^ { 2 } - 17 x + 12$$

Baholash

$$2x^{3}-\frac{17x^{2}}{2}+12x+С$$

Yechim qadamlari

Summani muddatma-muddat integratsiya qiling.

$$\int 6x^{2}\mathrm{d}x+\int -17x\mathrm{d}x+\int 12\mathrm{d}x$$

Har bir shartda konstantani qavsdan tashqariga oling.

$$6\int x^{2}\mathrm{d}x-17\int x\mathrm{d}x+\int 12\mathrm{d}x$$

k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x^{2}\mathrm{d}x integralni \frac{x^{3}}{3} bilan almashtiring. 6 ni \frac{x^{3}}{3} marotabaga ko'paytirish.

$$2x^{3}-17\int x\mathrm{d}x+\int 12\mathrm{d}x$$

k\neq -1 uchun integral \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} boʻlgani uchun, \int x\mathrm{d}x integralni \frac{x^{2}}{2} bilan almashtiring. -17 ni \frac{x^{2}}{2} marotabaga ko'paytirish.

$$2x^{3}-\frac{17x^{2}}{2}+\int 12\mathrm{d}x$$

\int a\mathrm{d}x=ax umumiy integrallar qoidasi jadvalidan foydalanib, 12 integralini toping.

$$2x^{3}-\frac{17x^{2}}{2}+12x$$

Агар F\left(x\right)f\left(x\right) ning dastlabki holati boʻlsa, u holatda f\left(x\right) ning barcha dastlabki holatlari toʻplami F\left(x\right)+C tarafidan belgilanadi. Shu sababli natijaga C\in \mathrm{R} integrallash konstantasini qoʻshing.

$$2x^{3}-\frac{17x^{2}}{2}+12x+С$$

x ga nisbatan hosilani topish

$$\left(2x-3\right)\left(3x-4\right)$$