∫ 2θdθ eching

$$\int 2 \theta d \theta$$

Baholash

$$С+\theta ^{2}$$

Yechim qadamlari

\int af\left(\theta \right)\mathrm{d}\theta =a\int f\left(\theta \right)\mathrm{d}\theta yordamidan konstantani qavsdan tashqariga chiqaring.

$$2\int \theta \mathrm{d}\theta$$

k\neq -1 uchun integral \int \theta ^{k}\mathrm{d}\theta =\frac{\theta ^{k+1}}{k+1} boʻlgani uchun, \int \theta \mathrm{d}\theta integralni \frac{\theta ^{2}}{2} bilan almashtiring. 2 ni \frac{\theta ^{2}}{2} marotabaga ko'paytirish.

$$\theta ^{2}$$

Агар F\left(\theta \right)f\left(\theta \right) ning dastlabki holati boʻlsa, u holatda f\left(\theta \right) ning barcha dastlabki holatlari toʻplami F\left(\theta \right)+C tarafidan belgilanadi. Shu sababli natijaga C\in \mathrm{R} integrallash konstantasini qoʻshing.

$$\theta ^{2}+С$$

θ ga nisbatan hosilani topish

$$2\theta$$