Baholash
\frac{x^{3}}{3}-\frac{3x^{2}}{2}+С
x ga nisbatan hosilani topish
x\left(x-3\right)
Baham ko'rish
Klipbordga nusxa olish
\int x^{2}\mathrm{d}x+\int -3x\mathrm{d}x
Integrate the sum term by term.
\int x^{2}\mathrm{d}x-3\int x\mathrm{d}x
Factor out the constant in each of the terms.
\frac{x^{3}}{3}-3\int x\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.
\frac{x^{3}}{3}-\frac{3x^{2}}{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. -3 ni \frac{x^{2}}{2} marotabaga ko'paytirish.
\frac{x^{3}}{3}-\frac{3x^{2}}{2}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
Misollar
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