∫ (x^2-1)e^-02x eching

$$\int ( x ^ { 2 } - 1 ) e ^ { - 02 x }$$

Baholash

$$\frac{x^{3}}{3}-x+С$$

Yechim qadamlari

0 hosil qilish uchun 0 va 2 ni ko'paytirish.

$$\int \left(x^{2}-1\right)e^{0x}\mathrm{d}x$$

Har qanday sonni nolga ko‘paytirsangiz, nol chiqadi.

$$\int \left(x^{2}-1\right)e^{0}\mathrm{d}x$$

0 daraja ko‘rsatkichini e ga hisoblang va 1 ni qiymatni oling.

$$\int \left(x^{2}-1\right)\times 1\mathrm{d}x$$

x^{2}-1 ga 1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\int x^{2}-1\mathrm{d}x$$

Integrate the sum term by term.

$$\int x^{2}\mathrm{d}x+\int -1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.

$$\frac{x^{3}}{3}+\int -1\mathrm{d}x$$

Find the integral of -1 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{x^{3}}{3}-x$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{3}}{3}-x+С$$

x ga nisbatan hosilani topish

$$x^{2}-1$$