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\int 1\mathrm{d}x+\int 2x^{4}\mathrm{d}x
Integrate the sum term by term.
\int 1\mathrm{d}x+2\int x^{4}\mathrm{d}x
Factor out the constant in each of the terms.
x+2\int x^{4}\mathrm{d}x
Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.
x+\frac{2x^{5}}{5}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{4}\mathrm{d}x with \frac{x^{5}}{5}. 2 ni \frac{x^{5}}{5} marotabaga ko'paytirish.
x+\frac{2x^{5}}{5}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.