gamma^2=operatorname{arcos}(55^2+76^2+93812/2(55)(76) eching

$$\gamma ^ { 2 } = \operatorname { arcos } ( \frac { 55 ^ { 2 } + 76 ^ { 2 } + 93812 } { 2 ( 55 ) ( 76 ) }$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}\text{, }&r\neq 0\\a\in \mathrm{C}\text{, }&\gamma =0\text{ and }r=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 55 ga hisoblang va 3025 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+76^{2}+93812}{2\times 55\times 76})$$

2 daraja ko‘rsatkichini 76 ga hisoblang va 5776 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+5776+93812}{2\times 55\times 76})$$

8801 olish uchun 3025 va 5776'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{8801+93812}{2\times 55\times 76})$$

102613 olish uchun 8801 va 93812'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{102613}{2\times 55\times 76})$$

110 hosil qilish uchun 2 va 55 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{110\times 76})$$

8360 hosil qilish uchun 110 va 76 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{8360})$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ar\cos(\frac{102613}{8360})=\gamma ^{2}$$

Tenglama standart shaklda.

$$\cos(\frac{102613}{8360})ra=\gamma ^{2}$$

Ikki tarafini r\cos(\frac{102613}{8360}) ga bo‘ling.

$$\frac{\cos(\frac{102613}{8360})ra}{\cos(\frac{102613}{8360})r}=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}$$

r\cos(\frac{102613}{8360}) ga bo'lish r\cos(\frac{102613}{8360}) ga ko'paytirishni bekor qiladi.

$$a=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}$$

r uchun yechish (complex solution)

$$\left\{\begin{matrix}r=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}\text{, }&a\neq 0\\r\in \mathrm{C}\text{, }&\gamma =0\text{ and }a=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 55 ga hisoblang va 3025 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+76^{2}+93812}{2\times 55\times 76})$$

2 daraja ko‘rsatkichini 76 ga hisoblang va 5776 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+5776+93812}{2\times 55\times 76})$$

8801 olish uchun 3025 va 5776'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{8801+93812}{2\times 55\times 76})$$

102613 olish uchun 8801 va 93812'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{102613}{2\times 55\times 76})$$

110 hosil qilish uchun 2 va 55 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{110\times 76})$$

8360 hosil qilish uchun 110 va 76 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{8360})$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ar\cos(\frac{102613}{8360})=\gamma ^{2}$$

Tenglama standart shaklda.

$$\cos(\frac{102613}{8360})ar=\gamma ^{2}$$

Ikki tarafini a\cos(\frac{102613}{8360}) ga bo‘ling.

$$\frac{\cos(\frac{102613}{8360})ar}{\cos(\frac{102613}{8360})a}=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}$$

a\cos(\frac{102613}{8360}) ga bo'lish a\cos(\frac{102613}{8360}) ga ko'paytirishni bekor qiladi.

$$r=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}\text{, }&r\neq 0\\a\in \mathrm{R}\text{, }&\gamma =0\text{ and }r=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 55 ga hisoblang va 3025 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+76^{2}+93812}{2\times 55\times 76})$$

2 daraja ko‘rsatkichini 76 ga hisoblang va 5776 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+5776+93812}{2\times 55\times 76})$$

8801 olish uchun 3025 va 5776'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{8801+93812}{2\times 55\times 76})$$

102613 olish uchun 8801 va 93812'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{102613}{2\times 55\times 76})$$

110 hosil qilish uchun 2 va 55 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{110\times 76})$$

8360 hosil qilish uchun 110 va 76 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{8360})$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ar\cos(\frac{102613}{8360})=\gamma ^{2}$$

Tenglama standart shaklda.

$$\cos(\frac{102613}{8360})ra=\gamma ^{2}$$

Ikki tarafini r\cos(\frac{102613}{8360}) ga bo‘ling.

$$\frac{\cos(\frac{102613}{8360})ra}{\cos(\frac{102613}{8360})r}=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}$$

r\cos(\frac{102613}{8360}) ga bo'lish r\cos(\frac{102613}{8360}) ga ko'paytirishni bekor qiladi.

$$a=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})r}$$

r uchun yechish

$$\left\{\begin{matrix}r=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}\text{, }&a\neq 0\\r\in \mathrm{R}\text{, }&\gamma =0\text{ and }a=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

2 daraja ko‘rsatkichini 55 ga hisoblang va 3025 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+76^{2}+93812}{2\times 55\times 76})$$

2 daraja ko‘rsatkichini 76 ga hisoblang va 5776 ni qiymatni oling.

$$\gamma ^{2}=ar\cos(\frac{3025+5776+93812}{2\times 55\times 76})$$

8801 olish uchun 3025 va 5776'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{8801+93812}{2\times 55\times 76})$$

102613 olish uchun 8801 va 93812'ni qo'shing.

$$\gamma ^{2}=ar\cos(\frac{102613}{2\times 55\times 76})$$

110 hosil qilish uchun 2 va 55 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{110\times 76})$$

8360 hosil qilish uchun 110 va 76 ni ko'paytirish.

$$\gamma ^{2}=ar\cos(\frac{102613}{8360})$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ar\cos(\frac{102613}{8360})=\gamma ^{2}$$

Tenglama standart shaklda.

$$\cos(\frac{102613}{8360})ar=\gamma ^{2}$$

Ikki tarafini a\cos(\frac{102613}{8360}) ga bo‘ling.

$$\frac{\cos(\frac{102613}{8360})ar}{\cos(\frac{102613}{8360})a}=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}$$

a\cos(\frac{102613}{8360}) ga bo'lish a\cos(\frac{102613}{8360}) ga ko'paytirishni bekor qiladi.

$$r=\frac{\gamma ^{2}}{\cos(\frac{102613}{8360})a}$$