162/n^2nleft(2n+1right)left(n+1right)/6 eching

$$\frac{ 162 }{ { n }^{ 2 } } \frac{ n \left( 2n+1 \right) \left( n+1 \right) }{ 6 }$$

Baholash

$$54n+81+\frac{27}{n}$$

Qisqa yechim qadamlari

n ga 2n+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{162}{n^{2}}\times \frac{\left(2n^{2}+n\right)\left(n+1\right)}{6}$$

2n^{2}+n ga n+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{162}{n^{2}}\times \frac{2n^{3}+3n^{2}+n}{6}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{162}{n^{2}} ni \frac{2n^{3}+3n^{2}+n}{6} ga ko‘paytiring.

$$\frac{162\left(2n^{3}+3n^{2}+n\right)}{n^{2}\times 6}$$

Surat va maxrajdagi ikkala 6 ni qisqartiring.

$$\frac{27\left(2n^{3}+3n^{2}+n\right)}{n^{2}}$$

Hali faktorlanmagan ifodalarni faktorlang.

$$\frac{27n\left(n+1\right)\left(2n+1\right)}{n^{2}}$$

Surat va maxrajdagi ikkala n ni qisqartiring.

$$\frac{27\left(n+1\right)\left(2n+1\right)}{n}$$

Ifodani kengaytiring.

$$\frac{54n^{2}+81n+27}{n}$$

Kengaytirish

$$54n+81+\frac{27}{n}$$

Qisqa yechim qadamlari

n ga 2n+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{162}{n^{2}}\times \frac{\left(2n^{2}+n\right)\left(n+1\right)}{6}$$

2n^{2}+n ga n+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{162}{n^{2}}\times \frac{2n^{3}+3n^{2}+n}{6}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{162}{n^{2}} ni \frac{2n^{3}+3n^{2}+n}{6} ga ko‘paytiring.

$$\frac{162\left(2n^{3}+3n^{2}+n\right)}{n^{2}\times 6}$$

Surat va maxrajdagi ikkala 6 ni qisqartiring.

$$\frac{27\left(2n^{3}+3n^{2}+n\right)}{n^{2}}$$

Hali faktorlanmagan ifodalarni faktorlang.

$$\frac{27n\left(n+1\right)\left(2n+1\right)}{n^{2}}$$

Surat va maxrajdagi ikkala n ni qisqartiring.

$$\frac{27\left(n+1\right)\left(2n+1\right)}{n}$$

Ifodani kengaytiring.

$$\frac{54n^{2}+81n+27}{n}$$