10-x/10-30=-5-50/-5-25 eching

$$\frac{ 10-x }{ 10-30 } = \frac{ -5-50 }{ -5-25 }$$

x uchun yechish

$$x = \frac{140}{3} = 46\frac{2}{3} \approx 46,666666667$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

-20 olish uchun 10 dan 30 ni ayirish.

$$\frac{10-x}{-20}=\frac{-5-50}{-5-25}$$

Surat va maxrajini -1 ga ko‘paytiring.

$$\frac{-10+x}{20}=\frac{-5-50}{-5-25}$$

-55 olish uchun -5 dan 50 ni ayirish.

$$\frac{-10+x}{20}=\frac{-55}{-5-25}$$

-30 olish uchun -5 dan 25 ni ayirish.

$$\frac{-10+x}{20}=\frac{-55}{-30}$$

\frac{-55}{-30} ulushini -5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{-10+x}{20}=\frac{11}{6}$$

-\frac{1}{2}+\frac{1}{20}x natijani olish uchun -10+x ning har bir ifodasini 20 ga bo‘ling.

$$-\frac{1}{2}+\frac{1}{20}x=\frac{11}{6}$$

\frac{1}{2} ni ikki tarafga qo’shing.

$$\frac{1}{20}x=\frac{11}{6}+\frac{1}{2}$$

6 va 2 ning eng kichik umumiy karralisi 6 ga teng. \frac{11}{6} va \frac{1}{2} ni 6 maxraj bilan kasrlarga aylantirib oling.

$$\frac{1}{20}x=\frac{11}{6}+\frac{3}{6}$$

\frac{11}{6} va \frac{3}{6} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{1}{20}x=\frac{11+3}{6}$$

14 olish uchun 11 va 3'ni qo'shing.

$$\frac{1}{20}x=\frac{14}{6}$$

\frac{14}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{1}{20}x=\frac{7}{3}$$

Ikki tarafini 20 va teskari kasri \frac{1}{20} ga ko‘paytiring.

$$x=\frac{7}{3}\times 20$$

\frac{7}{3}\times 20 ni yagona kasrga aylantiring.

$$x=\frac{7\times 20}{3}$$

140 hosil qilish uchun 7 va 20 ni ko'paytirish.

$$x=\frac{140}{3}$$