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6+48x-3\left(3x-1\right)=\frac{8}{3}\left(x+2\right)-48x
Tenglamaning ikkala tarafini 24 ga, 4,8,3,6 ning eng kichik karralisiga ko‘paytiring.
6+48x-9x+3=\frac{8}{3}\left(x+2\right)-48x
-3 ga 3x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
6+39x+3=\frac{8}{3}\left(x+2\right)-48x
39x ni olish uchun 48x va -9x ni birlashtirish.
9+39x=\frac{8}{3}\left(x+2\right)-48x
9 olish uchun 6 va 3'ni qo'shing.
9+39x=\frac{8}{3}x+\frac{8}{3}\times 2-48x
\frac{8}{3} ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
9+39x=\frac{8}{3}x+\frac{8\times 2}{3}-48x
\frac{8}{3}\times 2 ni yagona kasrga aylantiring.
9+39x=\frac{8}{3}x+\frac{16}{3}-48x
16 hosil qilish uchun 8 va 2 ni ko'paytirish.
9+39x=-\frac{136}{3}x+\frac{16}{3}
-\frac{136}{3}x ni olish uchun \frac{8}{3}x va -48x ni birlashtirish.
9+39x+\frac{136}{3}x=\frac{16}{3}
\frac{136}{3}x ni ikki tarafga qo’shing.
9+\frac{253}{3}x=\frac{16}{3}
\frac{253}{3}x ni olish uchun 39x va \frac{136}{3}x ni birlashtirish.
\frac{253}{3}x=\frac{16}{3}-9
Ikkala tarafdan 9 ni ayirish.
\frac{253}{3}x=\frac{16}{3}-\frac{27}{3}
9 ni \frac{27}{3} kasrga o‘giring.
\frac{253}{3}x=\frac{16-27}{3}
\frac{16}{3} va \frac{27}{3} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.
\frac{253}{3}x=-\frac{11}{3}
-11 olish uchun 16 dan 27 ni ayirish.
x=-\frac{11}{3}\times \frac{3}{253}
Ikki tarafini \frac{3}{253} va teskari kasri \frac{253}{3} ga ko‘paytiring.
x=\frac{-11\times 3}{3\times 253}
Suratni maxrajga va maxrajini suratga ko‘paytirish orqali -\frac{11}{3} ni \frac{3}{253} ga ko‘paytiring.
x=\frac{-11}{253}
Surat va maxrajdagi ikkala 3 ni qisqartiring.
x=-\frac{1}{23}
\frac{-11}{253} ulushini 11 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.