y-5/x-3=-2-(-1)/-3-4 eching

$$\frac { y - 5 } { x - 3 } = \frac { - 2 - ( - 1 ) } { - 3 - 4 }$$

x uchun yechish

$$x=7y-32$$

$$y\neq 5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati 3 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-3 ga ko'paytirish.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-2-\left(-1\right)\right)$$

-1 ning teskarisi 1 ga teng.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-2+1\right)$$

-1 olish uchun -2 va 1'ni qo'shing.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-1\right)$$

-\frac{1}{7}x+\frac{3}{7} ga -1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-5=\frac{1}{7}x-\frac{3}{7}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{1}{7}x-\frac{3}{7}=y-5$$

\frac{3}{7} ni ikki tarafga qo’shing.

$$\frac{1}{7}x=y-5+\frac{3}{7}$$

-\frac{32}{7} olish uchun -5 va \frac{3}{7}'ni qo'shing.

$$\frac{1}{7}x=y-\frac{32}{7}$$

Ikkala tarafini 7 ga ko‘paytiring.

$$\frac{\frac{1}{7}x}{\frac{1}{7}}=\frac{y-\frac{32}{7}}{\frac{1}{7}}$$

\frac{1}{7} ga bo'lish \frac{1}{7} ga ko'paytirishni bekor qiladi.

$$x=\frac{y-\frac{32}{7}}{\frac{1}{7}}$$

y-\frac{32}{7} ni \frac{1}{7} ga bo'lish y-\frac{32}{7} ga k'paytirish \frac{1}{7} ga qaytarish.

$$x=7y-32$$

x qiymati 3 teng bo‘lmaydi.

$$x=7y-32\text{, }x\neq 3$$

y uchun yechish

$$y=\frac{x+32}{7}$$

$$x\neq 3$$

Yechim qadamlari

Tenglamaning ikkala tarafini x-3 ga ko'paytirish.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-2-\left(-1\right)\right)$$

-1 ning teskarisi 1 ga teng.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-2+1\right)$$

-1 olish uchun -2 va 1'ni qo'shing.

$$y-5=\left(-\frac{1}{7}x+\frac{3}{7}\right)\left(-1\right)$$

-\frac{1}{7}x+\frac{3}{7} ga -1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$y-5=\frac{1}{7}x-\frac{3}{7}$$

5 ni ikki tarafga qo’shing.

$$y=\frac{1}{7}x-\frac{3}{7}+5$$

\frac{32}{7} olish uchun -\frac{3}{7} va 5'ni qo'shing.

$$y=\frac{1}{7}x+\frac{32}{7}$$