y/2y^2+7y+6 eching

$$\frac { y } { 2 y ^ { 2 } + 7 y + 6 }$$

y ga nisbatan hosilani topish

$$\frac{2\left(3-y^{2}\right)}{\left(\left(y+2\right)\left(2y+3\right)\right)^{2}}$$

Koeffitsient uchun derivativ qoidasidan foydalanish qadamlari

Har qanday ikki differensial funksiya uchun ikki funksiyaning koeffitsient hosilasi raqamlagichning hosila marotabasi maxraj minusi va barchasi kvadrat maxrajiga bo'lingan.

$$\frac{\left(2y^{2}+7y^{1}+6\right)\frac{\mathrm{d}}{\mathrm{d}y}(y^{1})-y^{1}\frac{\mathrm{d}}{\mathrm{d}y}(2y^{2}+7y^{1}+6)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

Polinomialning hosilasi bu uning shartlari hosilasining yig‘indisiga teng. Konstant shartning hosilasi 0. ax^{n} ning hosilasi nax^{n-1}.

$$\frac{\left(2y^{2}+7y^{1}+6\right)y^{1-1}-y^{1}\left(2\times 2y^{2-1}+7y^{1-1}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

Qisqartirish.

$$\frac{\left(2y^{2}+7y^{1}+6\right)y^{0}-y^{1}\left(4y^{1}+7y^{0}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

2y^{2}+7y^{1}+6 ni y^{0} marotabaga ko'paytirish.

$$\frac{2y^{2}y^{0}+7y^{1}y^{0}+6y^{0}-y^{1}\left(4y^{1}+7y^{0}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

y^{1} ni 4y^{1}+7y^{0} marotabaga ko'paytirish.

$$\frac{2y^{2}y^{0}+7y^{1}y^{0}+6y^{0}-\left(y^{1}\times 4y^{1}+y^{1}\times 7y^{0}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

Ayni daraja ko'rsatkichlarini ko'paytirish uchun ularning darajalarini qo'shing.

$$\frac{2y^{2}+7y^{1}+6y^{0}-\left(4y^{1+1}+7y^{1}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

Qisqartirish.

$$\frac{2y^{2}+7y^{1}+6y^{0}-\left(4y^{2}+7y^{1}\right)}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

O'xshash hadlarni birlashtirish.

$$\frac{-2y^{2}+6y^{0}}{\left(2y^{2}+7y^{1}+6\right)^{2}}$$

Har qanday t sharti uchun t^{1}=t.

$$\frac{-2y^{2}+6y^{0}}{\left(2y^{2}+7y+6\right)^{2}}$$

Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.

$$\frac{-2y^{2}+6\times 1}{\left(2y^{2}+7y+6\right)^{2}}$$

Har qanday t sharti uchun t\times 1=t va 1t=t.

$$\frac{-2y^{2}+6}{\left(2y^{2}+7y+6\right)^{2}}$$

Baholash

$$\frac{y}{\left(y+2\right)\left(2y+3\right)}$$