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\left(x+1\right)\left(x-4\right)=\left(x+3\right)\left(x-3\right)
x qiymati -3,-1 qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(x+1\right)\left(x+3\right) ga, x+3,x+1 ning eng kichik karralisiga ko‘paytiring.
x^{2}-3x-4=\left(x+3\right)\left(x-3\right)
x+1 ga x-4 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.
x^{2}-3x-4=x^{2}-9
Hisoblang: \left(x+3\right)\left(x-3\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. 3 kvadratini chiqarish.
x^{2}-3x-4-x^{2}=-9
Ikkala tarafdan x^{2} ni ayirish.
-3x-4=-9
0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.
-3x=-9+4
4 ni ikki tarafga qo’shing.
-3x=-5
-5 olish uchun -9 va 4'ni qo'shing.
x=\frac{-5}{-3}
Ikki tarafini -3 ga bo‘ling.
x=\frac{5}{3}
Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-5}{-3} kasrini \frac{5}{3} ga soddalashtirish mumkin.