x/a+x/b=dx/-3+3 eching

$$\frac { x } { a } + \frac { x } { b } = \frac { d x } { - 3 } + 3$$

a uchun yechish

$$a=-\frac{3bx}{bdx+3x-9b}$$

$$\left(b\neq 0\text{ and }x\neq 0\text{ and }x\neq \frac{9b}{bd+3}\text{ and }x\neq 3b\right)\text{ or }\left(b\neq 0\text{ and }x\neq 0\text{ and }x\neq \frac{9b}{bd+3}\text{ and }d\neq 0\right)\text{ or }\left(x\neq 0\text{ and }b=-\frac{3}{d}\text{ and }d\neq 0\right)$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

a qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 3ab ga, a,b,-3 ning eng kichik karralisiga ko‘paytiring.

$$3bx+3ax=-abdx+3ab\times 3$$

9 hosil qilish uchun 3 va 3 ni ko'paytirish.

$$3bx+3ax=-abdx+9ab$$

abdx ni ikki tarafga qo’shing.

$$3bx+3ax+abdx=9ab$$

Ikkala tarafdan 9ab ni ayirish.

$$3bx+3ax+abdx-9ab=0$$

Ikkala tarafdan 3bx ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$3ax+abdx-9ab=-3bx$$

a'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(3x+bdx-9b\right)a=-3bx$$

Tenglama standart shaklda.

$$\left(bdx+3x-9b\right)a=-3bx$$

Ikki tarafini 3x+bdx-9b ga bo‘ling.

$$\frac{\left(bdx+3x-9b\right)a}{bdx+3x-9b}=-\frac{3bx}{bdx+3x-9b}$$

3x+bdx-9b ga bo'lish 3x+bdx-9b ga ko'paytirishni bekor qiladi.

$$a=-\frac{3bx}{bdx+3x-9b}$$

a qiymati 0 teng bo‘lmaydi.

$$a=-\frac{3bx}{bdx+3x-9b}\text{, }a\neq 0$$

b uchun yechish

$$b=-\frac{3ax}{adx+3x-9a}$$

$$\left(a\neq 0\text{ and }x\neq 0\text{ and }x\neq \frac{9a}{ad+3}\text{ and }x\neq 3a\right)\text{ or }\left(a\neq 0\text{ and }x\neq 0\text{ and }x\neq \frac{9a}{ad+3}\text{ and }d\neq 0\right)\text{ or }\left(x\neq 0\text{ and }a=-\frac{3}{d}\text{ and }d\neq 0\right)$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

b qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 3ab ga, a,b,-3 ning eng kichik karralisiga ko‘paytiring.

$$3bx+3ax=-abdx+3ab\times 3$$

9 hosil qilish uchun 3 va 3 ni ko'paytirish.

$$3bx+3ax=-abdx+9ab$$

abdx ni ikki tarafga qo’shing.

$$3bx+3ax+abdx=9ab$$

Ikkala tarafdan 9ab ni ayirish.

$$3bx+3ax+abdx-9ab=0$$

Ikkala tarafdan 3ax ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$3bx+abdx-9ab=-3ax$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(3x+adx-9a\right)b=-3ax$$

Tenglama standart shaklda.

$$\left(adx+3x-9a\right)b=-3ax$$

Ikki tarafini 3x+adx-9a ga bo‘ling.

$$\frac{\left(adx+3x-9a\right)b}{adx+3x-9a}=-\frac{3ax}{adx+3x-9a}$$

3x+adx-9a ga bo'lish 3x+adx-9a ga ko'paytirishni bekor qiladi.

$$b=-\frac{3ax}{adx+3x-9a}$$

b qiymati 0 teng bo‘lmaydi.

$$b=-\frac{3ax}{adx+3x-9a}\text{, }b\neq 0$$