x uchun yechish
x=-5
Grafik
Baham ko'rish
Klipbordga nusxa olish
\left(x+4\right)\left(x+3\right)=\left(x+7\right)\left(x+6\right)
x qiymati -7,-4 qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(x+4\right)\left(x+7\right) ga, x+7,x+4 ning eng kichik karralisiga ko‘paytiring.
x^{2}+7x+12=\left(x+7\right)\left(x+6\right)
x+4 ga x+3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.
x^{2}+7x+12=x^{2}+13x+42
x+7 ga x+6 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.
x^{2}+7x+12-x^{2}=13x+42
Ikkala tarafdan x^{2} ni ayirish.
7x+12=13x+42
0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.
7x+12-13x=42
Ikkala tarafdan 13x ni ayirish.
-6x+12=42
-6x ni olish uchun 7x va -13x ni birlashtirish.
-6x=42-12
Ikkala tarafdan 12 ni ayirish.
-6x=30
30 olish uchun 42 dan 12 ni ayirish.
x=\frac{30}{-6}
Ikki tarafini -6 ga bo‘ling.
x=-5
-5 ni olish uchun 30 ni -6 ga bo‘ling.
Misollar
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simli tenglama
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Chegaralar
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