x+1/z-1=2i eching

$$\frac { x + 1 } { z - 1 } = 2 i$$

z uchun yechish

$$z=-\frac{ix}{2}+\left(1-\frac{1}{2}i\right)$$

$$x\neq -1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

z qiymati 1 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini z-1 ga ko'paytirish.

$$x+1=2i\left(z-1\right)$$

2i ga z-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+1=2iz-2i$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2iz-2i=x+1$$

2i ni ikki tarafga qo’shing.

$$2iz=x+1+2i$$

Tenglama standart shaklda.

$$2iz=x+\left(1+2i\right)$$

Ikki tarafini 2i ga bo‘ling.

$$\frac{2iz}{2i}=\frac{x+\left(1+2i\right)}{2i}$$

2i ga bo'lish 2i ga ko'paytirishni bekor qiladi.

$$z=\frac{x+\left(1+2i\right)}{2i}$$

x+\left(1+2i\right) ni 2i ga bo'lish.

$$z=-\frac{ix}{2}+\left(1-\frac{1}{2}i\right)$$

z qiymati 1 teng bo‘lmaydi.

$$z=-\frac{ix}{2}+\left(1-\frac{1}{2}i\right)\text{, }z\neq 1$$

x uchun yechish

$$x=2iz+\left(-1-2i\right)$$

$$z\neq 1$$