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\left(x+1\right)\left(x+1\right)=\left(x+2\right)\left(x-3\right)
x qiymati -2,-1 qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(x+1\right)\left(x+2\right) ga, x+2,x+1 ning eng kichik karralisiga ko‘paytiring.
\left(x+1\right)^{2}=\left(x+2\right)\left(x-3\right)
\left(x+1\right)^{2} hosil qilish uchun x+1 va x+1 ni ko'paytirish.
x^{2}+2x+1=\left(x+2\right)\left(x-3\right)
\left(a+b\right)^{2}=a^{2}+2ab+b^{2} binom teoremasini \left(x+1\right)^{2} kengaytirilishi uchun ishlating.
x^{2}+2x+1=x^{2}-x-6
x+2 ga x-3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.
x^{2}+2x+1-x^{2}=-x-6
Ikkala tarafdan x^{2} ni ayirish.
2x+1=-x-6
0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.
2x+1+x=-6
x ni ikki tarafga qo’shing.
3x+1=-6
3x ni olish uchun 2x va x ni birlashtirish.
3x=-6-1
Ikkala tarafdan 1 ni ayirish.
3x=-7
-7 olish uchun -6 dan 1 ni ayirish.
x=\frac{-7}{3}
Ikki tarafini 3 ga bo‘ling.
x=-\frac{7}{3}
\frac{-7}{3} kasri manfiy belgini olib tashlash bilan -\frac{7}{3} sifatida qayta yozilishi mumkin.