j-8/j+10=j-1/j+3 eching

$$\frac { j - 8 } { j + 10 } = \frac { j - 1 } { j + 3 }$$

j uchun yechish

$$j=-1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

j qiymati -10,-3 qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(j+3\right)\left(j+10\right) ga, j+10,j+3 ning eng kichik karralisiga ko‘paytiring.

$$\left(j+3\right)\left(j-8\right)=\left(j+10\right)\left(j-1\right)$$

j+3 ga j-8 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$j^{2}-5j-24=\left(j+10\right)\left(j-1\right)$$

j+10 ga j-1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$j^{2}-5j-24=j^{2}+9j-10$$

Ikkala tarafdan j^{2} ni ayirish.

$$j^{2}-5j-24-j^{2}=9j-10$$

0 ni olish uchun j^{2} va -j^{2} ni birlashtirish.

$$-5j-24=9j-10$$

Ikkala tarafdan 9j ni ayirish.

$$-5j-24-9j=-10$$

-14j ni olish uchun -5j va -9j ni birlashtirish.

$$-14j-24=-10$$

24 ni ikki tarafga qo’shing.

$$-14j=-10+24$$

14 olish uchun -10 va 24'ni qo'shing.

$$-14j=14$$

Ikki tarafini -14 ga bo‘ling.

$$j=\frac{14}{-14}$$

-1 ni olish uchun 14 ni -14 ga bo‘ling.

$$j=-1$$