g/9g+49=1/g+9 eching

$$\frac { g } { 9 g + 49 } = \frac { 1 } { g + 9 }$$

g uchun yechish

$$g=-7$$

$$g=7$$

Kvadrat ildizini topish bo'yicha qadamlar

g qiymati -9,-\frac{49}{9} qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(g+9\right)\left(9g+49\right) ga, 9g+49,g+9 ning eng kichik karralisiga ko‘paytiring.

$$\left(g+9\right)g=9g+49$$

g+9 ga g ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$g^{2}+9g=9g+49$$

Ikkala tarafdan 9g ni ayirish.

$$g^{2}+9g-9g=49$$

0 ni olish uchun 9g va -9g ni birlashtirish.

$$g^{2}=49$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$g=7 g=-7$$

Kvadrat tenglamalaridan foydalanish qoidalari

g qiymati -9,-\frac{49}{9} qiymatlaridan birortasiga teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(g+9\right)\left(9g+49\right) ga, 9g+49,g+9 ning eng kichik karralisiga ko‘paytiring.

$$\left(g+9\right)g=9g+49$$

g+9 ga g ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$g^{2}+9g=9g+49$$

Ikkala tarafdan 9g ni ayirish.

$$g^{2}+9g-9g=49$$

0 ni olish uchun 9g va -9g ni birlashtirish.

$$g^{2}=49$$

Ikkala tarafdan 49 ni ayirish.

$$g^{2}-49=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -49 ni c bilan almashtiring.

$$g=\frac{0±\sqrt{0^{2}-4\left(-49\right)}}{2}$$

0 kvadratini chiqarish.

$$g=\frac{0±\sqrt{-4\left(-49\right)}}{2}$$

-4 ni -49 marotabaga ko'paytirish.

$$g=\frac{0±\sqrt{196}}{2}$$

196 ning kvadrat ildizini chiqarish.

$$g=\frac{0±14}{2}$$

g=\frac{0±14}{2} tenglamasini yeching, bunda ± musbat. 14 ni 2 ga bo'lish.

$$g=7$$

g=\frac{0±14}{2} tenglamasini yeching, bunda ± manfiy. -14 ni 2 ga bo'lish.

$$g=-7$$

Tenglama yechildi.

$$g=7 g=-7$$