dx/dx=2sqrt{x}dx eching

$$\frac { d x } { d x } = 2 \sqrt { x } d x$$

d uchun yechish

$$d=\frac{1}{2x^{\frac{3}{2}}}$$

$$x>0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$2\sqrt{x}dx=\frac{\mathrm{d}(x)}{\mathrm{d}x}$$

Tenglama standart shaklda.

$$2\sqrt{x}xd=1$$

Ikki tarafini 2\sqrt{x}x ga bo‘ling.

$$\frac{2\sqrt{x}xd}{2\sqrt{x}x}=\frac{1}{2\sqrt{x}x}$$

2\sqrt{x}x ga bo'lish 2\sqrt{x}x ga ko'paytirishni bekor qiladi.

$$d=\frac{1}{2\sqrt{x}x}$$

1 ni 2\sqrt{x}x ga bo'lish.

$$d=\frac{1}{2x^{\frac{3}{2}}}$$

x uchun yechish

$$x=\frac{\left(\frac{4}{d}\right)^{\frac{2}{3}}}{4}$$

$$d>0$$