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\frac{\left(b+3\right)\left(20b+70\right)}{\left(a+2a\right)\times 7}
\frac{b+3}{a+2a} ni \frac{7}{20b+70} ga bo'lish \frac{b+3}{a+2a} ga k'paytirish \frac{7}{20b+70} ga qaytarish.
\frac{\left(b+3\right)\left(20b+70\right)}{3a\times 7}
3a ni olish uchun a va 2a ni birlashtirish.
\frac{\left(b+3\right)\left(20b+70\right)}{21a}
21 hosil qilish uchun 3 va 7 ni ko'paytirish.
\frac{20b^{2}+70b+60b+210}{21a}
b+3 ifodaning har bir elementini 20b+70 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
\frac{20b^{2}+130b+210}{21a}
130b ni olish uchun 70b va 60b ni birlashtirish.
\frac{\left(b+3\right)\left(20b+70\right)}{\left(a+2a\right)\times 7}
\frac{b+3}{a+2a} ni \frac{7}{20b+70} ga bo'lish \frac{b+3}{a+2a} ga k'paytirish \frac{7}{20b+70} ga qaytarish.
\frac{\left(b+3\right)\left(20b+70\right)}{3a\times 7}
3a ni olish uchun a va 2a ni birlashtirish.
\frac{\left(b+3\right)\left(20b+70\right)}{21a}
21 hosil qilish uchun 3 va 7 ni ko'paytirish.
\frac{20b^{2}+70b+60b+210}{21a}
b+3 ifodaning har bir elementini 20b+70 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
\frac{20b^{2}+130b+210}{21a}
130b ni olish uchun 70b va 60b ni birlashtirish.