ax/x+b=y eching

$$\frac { a x } { x + b } = y$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=\frac{y\left(x+b\right)}{x}\text{, }&x\neq 0\text{ and }x\neq -b\\a\in \mathrm{C}\text{, }&y=0\text{ and }x=0\text{ and }b\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini x+b ga ko'paytirish.

$$ax=y\left(x+b\right)$$

y ga x+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax=yx+yb$$

Tenglama standart shaklda.

$$xa=xy+by$$

Ikki tarafini x ga bo‘ling.

$$\frac{xa}{x}=\frac{y\left(x+b\right)}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$a=\frac{y\left(x+b\right)}{x}$$

a uchun yechish

$$\left\{\begin{matrix}a=\frac{y\left(x+b\right)}{x}\text{, }&x\neq 0\text{ and }x\neq -b\\a\in \mathrm{R}\text{, }&y=0\text{ and }x=0\text{ and }b\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini x+b ga ko'paytirish.

$$ax=y\left(x+b\right)$$

y ga x+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$ax=yx+yb$$

Tenglama standart shaklda.

$$xa=xy+by$$

Ikki tarafini x ga bo‘ling.

$$\frac{xa}{x}=\frac{y\left(x+b\right)}{x}$$

x ga bo'lish x ga ko'paytirishni bekor qiladi.

$$a=\frac{y\left(x+b\right)}{x}$$

b uchun yechish

$$\left\{\begin{matrix}b=\frac{x\left(a-y\right)}{y}\text{, }&x\neq 0\text{ and }a\neq 0\text{ and }y\neq 0\\b\neq -x\text{, }&x\neq 0\text{ and }y=0\text{ and }a=0\\b\neq 0\text{, }&y=0\text{ and }x=0\end{matrix}\right,$$