ax+b/3=cx+d/2 eching

$$\frac { a x + b } { 3 } = \frac { c x + d } { 2 }$$

a uchun yechish (complex solution)

$$\left\{\begin{matrix}a=-\frac{-3cx+2b-3d}{2x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=\frac{3d}{2}\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 6 ga, 3,2 ning eng kichik karralisiga ko‘paytiring.

$$2\left(ax+b\right)=3\left(cx+d\right)$$

2 ga ax+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3\left(cx+d\right)$$

3 ga cx+d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3cx+3d$$

Ikkala tarafdan 2b ni ayirish.

$$2ax=3cx+3d-2b$$

Tenglama standart shaklda.

$$2xa=3cx+3d-2b$$

Ikki tarafini 2x ga bo‘ling.

$$\frac{2xa}{2x}=\frac{3cx+3d-2b}{2x}$$

2x ga bo'lish 2x ga ko'paytirishni bekor qiladi.

$$a=\frac{3cx+3d-2b}{2x}$$

a uchun yechish

$$\left\{\begin{matrix}a=-\frac{-3cx+2b-3d}{2x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=\frac{3d}{2}\text{ and }x=0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 6 ga, 3,2 ning eng kichik karralisiga ko‘paytiring.

$$2\left(ax+b\right)=3\left(cx+d\right)$$

2 ga ax+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3\left(cx+d\right)$$

3 ga cx+d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3cx+3d$$

Ikkala tarafdan 2b ni ayirish.

$$2ax=3cx+3d-2b$$

Tenglama standart shaklda.

$$2xa=3cx+3d-2b$$

Ikki tarafini 2x ga bo‘ling.

$$\frac{2xa}{2x}=\frac{3cx+3d-2b}{2x}$$

2x ga bo'lish 2x ga ko'paytirishni bekor qiladi.

$$a=\frac{3cx+3d-2b}{2x}$$

b uchun yechish

$$b=-ax+\frac{3cx}{2}+\frac{3d}{2}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 6 ga, 3,2 ning eng kichik karralisiga ko‘paytiring.

$$2\left(ax+b\right)=3\left(cx+d\right)$$

2 ga ax+b ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3\left(cx+d\right)$$

3 ga cx+d ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$2ax+2b=3cx+3d$$

Ikkala tarafdan 2ax ni ayirish.

$$2b=3cx+3d-2ax$$

Tenglama standart shaklda.

$$2b=3cx-2ax+3d$$

Ikki tarafini 2 ga bo‘ling.

$$\frac{2b}{2}=\frac{3cx-2ax+3d}{2}$$

2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.

$$b=\frac{3cx-2ax+3d}{2}$$

3cx+3d-2ax ni 2 ga bo'lish.

$$b=-ax+\frac{3cx}{2}+\frac{3d}{2}$$