BC+10/sqrt{3}=BC eching

$$\frac { B C + 10 } { \sqrt { 3 } } = B C$$

B uchun yechish

$$B=\frac{5\left(\sqrt{3}+1\right)}{C}$$

$$C\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{BC+10}{\sqrt{3}} maxrajini \sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$\frac{\left(BC+10\right)\sqrt{3}}{\left(\sqrt{3}\right)^{2}}=BC$$

\sqrt{3} kvadrati – 3.

$$\frac{\left(BC+10\right)\sqrt{3}}{3}=BC$$

BC+10 ga \sqrt{3} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{BC\sqrt{3}+10\sqrt{3}}{3}=BC$$

Ikkala tarafdan BC ni ayirish.

$$\frac{BC\sqrt{3}+10\sqrt{3}}{3}-BC=0$$

Tenglamaning ikkala tarafini 3 ga ko'paytirish.

$$BC\sqrt{3}+10\sqrt{3}-3BC=0$$

Shartlarni qayta saralash.

$$\sqrt{3}BC-3BC+10\sqrt{3}=0$$

Ikkala tarafdan 10\sqrt{3} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$\sqrt{3}BC-3BC=-10\sqrt{3}$$

B'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(\sqrt{3}C-3C\right)B=-10\sqrt{3}$$

Ikki tarafini \sqrt{3}C-3C ga bo‘ling.

$$\frac{\left(\sqrt{3}C-3C\right)B}{\sqrt{3}C-3C}=-\frac{10\sqrt{3}}{\sqrt{3}C-3C}$$

\sqrt{3}C-3C ga bo'lish \sqrt{3}C-3C ga ko'paytirishni bekor qiladi.

$$B=-\frac{10\sqrt{3}}{\sqrt{3}C-3C}$$

-10\sqrt{3} ni \sqrt{3}C-3C ga bo'lish.

$$B=\frac{5\left(\sqrt{3}+1\right)}{C}$$

C uchun yechish

$$C=\frac{5\left(\sqrt{3}+1\right)}{B}$$

$$B\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{BC+10}{\sqrt{3}} maxrajini \sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$\frac{\left(BC+10\right)\sqrt{3}}{\left(\sqrt{3}\right)^{2}}=BC$$

\sqrt{3} kvadrati – 3.

$$\frac{\left(BC+10\right)\sqrt{3}}{3}=BC$$

BC+10 ga \sqrt{3} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{BC\sqrt{3}+10\sqrt{3}}{3}=BC$$

Ikkala tarafdan BC ni ayirish.

$$\frac{BC\sqrt{3}+10\sqrt{3}}{3}-BC=0$$

Tenglamaning ikkala tarafini 3 ga ko'paytirish.

$$BC\sqrt{3}+10\sqrt{3}-3BC=0$$

Shartlarni qayta saralash.

$$\sqrt{3}BC-3BC+10\sqrt{3}=0$$

Ikkala tarafdan 10\sqrt{3} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$\sqrt{3}BC-3BC=-10\sqrt{3}$$

C'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(\sqrt{3}B-3B\right)C=-10\sqrt{3}$$

Ikki tarafini \sqrt{3}B-3B ga bo‘ling.

$$\frac{\left(\sqrt{3}B-3B\right)C}{\sqrt{3}B-3B}=-\frac{10\sqrt{3}}{\sqrt{3}B-3B}$$

\sqrt{3}B-3B ga bo'lish \sqrt{3}B-3B ga ko'paytirishni bekor qiladi.

$$C=-\frac{10\sqrt{3}}{\sqrt{3}B-3B}$$

-10\sqrt{3} ni \sqrt{3}B-3B ga bo'lish.

$$C=\frac{5\left(\sqrt{3}+1\right)}{B}$$