8(x+5)/10-2/5geq1 eching

$$\frac { 8 ( x + 5 ) } { 10 } - \frac { 2 } { 5 } \geq 1$$

x uchun yechish

$$x\geq -\frac{13}{4}$$

Yechim qadamlari

Tenglamaning ikkala tarafini 10 ga, 10,5 ning eng kichik karralisiga ko‘paytiring. 10 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$8\left(x+5\right)-4\geq 10$$

8 ga x+5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$8x+40-4\geq 10$$

36 olish uchun 40 dan 4 ni ayirish.

$$8x+36\geq 10$$

Ikkala tarafdan 36 ni ayirish.

$$8x\geq 10-36$$

-26 olish uchun 10 dan 36 ni ayirish.

$$8x\geq -26$$

Ikki tarafini 8 ga bo‘ling. 8 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x\geq \frac{-26}{8}$$

\frac{-26}{8} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x\geq -\frac{13}{4}$$