6/1-4-3x/x^2-4= eching

$$\frac { 6 } { 1 - 4 } - \frac { 3 x } { x ^ { 2 } - 4 } =$$

Baholash

$$\frac{8-3x-2x^{2}}{x^{2}-4}$$

Qisqa yechim qadamlari

-3 olish uchun 1 dan 4 ni ayirish.

$$\frac{6}{-3}-\frac{3x}{x^{2}-4}$$

-2 ni olish uchun 6 ni -3 ga bo‘ling.

$$-2-\frac{3x}{x^{2}-4}$$

Faktor: x^{2}-4.

$$-2-\frac{3x}{\left(x-2\right)\left(x+2\right)}$$

Ifodalarni qo‘shish yoki ayirish uchun ularni yoyib, maxrajlarini bir xil qiling. -2 ni \frac{\left(x-2\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)} marotabaga ko'paytirish.

$$-\frac{2\left(x-2\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}-\frac{3x}{\left(x-2\right)\left(x+2\right)}$$

-\frac{2\left(x-2\right)\left(x+2\right)}{\left(x-2\right)\left(x+2\right)} va \frac{3x}{\left(x-2\right)\left(x+2\right)} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{-2\left(x-2\right)\left(x+2\right)-3x}{\left(x-2\right)\left(x+2\right)}$$

-2\left(x-2\right)\left(x+2\right)-3x ichidagi ko‘paytirishlarni bajaring.

$$\frac{-2x^{2}-4x+4x+8-3x}{\left(x-2\right)\left(x+2\right)}$$

-2x^{2}-4x+4x+8-3x kabi iboralarga o‘xshab birlashtiring.

$$\frac{-2x^{2}-3x+8}{\left(x-2\right)\left(x+2\right)}$$

\left(x-2\right)\left(x+2\right) ni kengaytirish.

$$\frac{-2x^{2}-3x+8}{x^{2}-4}$$

Omil

$$-\frac{2\left(x-\frac{-\sqrt{73}-3}{4}\right)\left(x-\frac{\sqrt{73}-3}{4}\right)}{x^{2}-4}$$