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Veb-qidiruvdagi o'xshash muammolar

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6x+\frac{2}{10}x
Har qanday son birga bo‘linganda, natija o‘zi chiqadi.
6x+\frac{1}{5}x
\frac{2}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{31}{5}x
\frac{31}{5}x ni olish uchun 6x va \frac{1}{5}x ni birlashtirish.
\frac{\mathrm{d}}{\mathrm{d}x}(6x+\frac{2}{10}x)
Har qanday son birga bo‘linganda, natija o‘zi chiqadi.
\frac{\mathrm{d}}{\mathrm{d}x}(6x+\frac{1}{5}x)
\frac{2}{10} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{31}{5}x)
\frac{31}{5}x ni olish uchun 6x va \frac{1}{5}x ni birlashtirish.
\frac{31}{5}x^{1-1}
ax^{n} hosilasi – nax^{n-1}.
\frac{31}{5}x^{0}
1 dan 1 ni ayirish.
\frac{31}{5}\times 1
Har qanday t sharti uchun (0 bundan mustasno) t^{0}=1.
\frac{31}{5}
Har qanday t sharti uchun t\times 1=t va 1t=t.