5/6(sqrt{3+2)} eching

$$\frac { 5 } { 6 ( \sqrt { 3 } + 2 ) }$$

Baholash

$$-\frac{5\sqrt{3}}{6}+\frac{5}{3}\approx 0,223290994$$

Yechim qadamlari

6 ga \sqrt{3}+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{5}{6\sqrt{3}+12}$$

\frac{5}{6\sqrt{3}+12} maxrajini 6\sqrt{3}-12 orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

$$\frac{5\left(6\sqrt{3}-12\right)}{\left(6\sqrt{3}+12\right)\left(6\sqrt{3}-12\right)}$$

Hisoblang: \left(6\sqrt{3}+12\right)\left(6\sqrt{3}-12\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{5\left(6\sqrt{3}-12\right)}{\left(6\sqrt{3}\right)^{2}-12^{2}}$$

\left(6\sqrt{3}\right)^{2} ni kengaytirish.

$$\frac{5\left(6\sqrt{3}-12\right)}{6^{2}\left(\sqrt{3}\right)^{2}-12^{2}}$$

2 daraja ko‘rsatkichini 6 ga hisoblang va 36 ni qiymatni oling.

$$\frac{5\left(6\sqrt{3}-12\right)}{36\left(\sqrt{3}\right)^{2}-12^{2}}$$

\sqrt{3} kvadrati – 3.

$$\frac{5\left(6\sqrt{3}-12\right)}{36\times 3-12^{2}}$$

108 hosil qilish uchun 36 va 3 ni ko'paytirish.

$$\frac{5\left(6\sqrt{3}-12\right)}{108-12^{2}}$$

2 daraja ko‘rsatkichini 12 ga hisoblang va 144 ni qiymatni oling.

$$\frac{5\left(6\sqrt{3}-12\right)}{108-144}$$

-36 olish uchun 108 dan 144 ni ayirish.

$$\frac{5\left(6\sqrt{3}-12\right)}{-36}$$

5 ga 6\sqrt{3}-12 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{30\sqrt{3}-60}{-36}$$