5/6x-5/3geq1/3+1/2x eching

$$\frac { 5 } { 6 } x - \frac { 5 } { 3 } \geq \frac { 1 } { 3 } + \frac { 1 } { 2 } x$$

x uchun yechish

$$x\geq 6$$

Yechim qadamlari

Ikkala tarafdan \frac{1}{2}x ni ayirish.

$$\frac{5}{6}x-\frac{5}{3}-\frac{1}{2}x\geq \frac{1}{3}$$

\frac{1}{3}x ni olish uchun \frac{5}{6}x va -\frac{1}{2}x ni birlashtirish.

$$\frac{1}{3}x-\frac{5}{3}\geq \frac{1}{3}$$

\frac{5}{3} ni ikki tarafga qo’shing.

$$\frac{1}{3}x\geq \frac{1}{3}+\frac{5}{3}$$

\frac{1}{3} va \frac{5}{3} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{1}{3}x\geq \frac{1+5}{3}$$

6 olish uchun 1 va 5'ni qo'shing.

$$\frac{1}{3}x\geq \frac{6}{3}$$

2 ni olish uchun 6 ni 3 ga bo‘ling.

$$\frac{1}{3}x\geq 2$$

Ikki tarafini 3 va teskari kasri \frac{1}{3} ga ko‘paytiring. \frac{1}{3} musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x\geq 2\times 3$$

6 hosil qilish uchun 2 va 3 ni ko'paytirish.

$$x\geq 6$$