x uchun yechish
x = -\frac{6}{5} = -1\frac{1}{5} = -1,2
x=0
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Klipbordga nusxa olish
x\left(\frac{5}{3}x+2\right)=0
x omili.
x=0 x=-\frac{6}{5}
Tenglamani yechish uchun x=0 va \frac{5x}{3}+2=0 ni yeching.
\frac{5}{3}x^{2}+2x=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-2±\sqrt{2^{2}}}{2\times \frac{5}{3}}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} \frac{5}{3} ni a, 2 ni b va 0 ni c bilan almashtiring.
x=\frac{-2±2}{2\times \frac{5}{3}}
2^{2} ning kvadrat ildizini chiqarish.
x=\frac{-2±2}{\frac{10}{3}}
2 ni \frac{5}{3} marotabaga ko'paytirish.
x=\frac{0}{\frac{10}{3}}
x=\frac{-2±2}{\frac{10}{3}} tenglamasini yeching, bunda ± musbat. -2 ni 2 ga qo'shish.
x=0
0 ni \frac{10}{3} ga bo'lish 0 ga k'paytirish \frac{10}{3} ga qaytarish.
x=-\frac{4}{\frac{10}{3}}
x=\frac{-2±2}{\frac{10}{3}} tenglamasini yeching, bunda ± manfiy. -2 dan 2 ni ayirish.
x=-\frac{6}{5}
-4 ni \frac{10}{3} ga bo'lish -4 ga k'paytirish \frac{10}{3} ga qaytarish.
x=0 x=-\frac{6}{5}
Tenglama yechildi.
\frac{5}{3}x^{2}+2x=0
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
\frac{\frac{5}{3}x^{2}+2x}{\frac{5}{3}}=\frac{0}{\frac{5}{3}}
Tenglamaning ikki tarafini \frac{5}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.
x^{2}+\frac{2}{\frac{5}{3}}x=\frac{0}{\frac{5}{3}}
\frac{5}{3} ga bo'lish \frac{5}{3} ga ko'paytirishni bekor qiladi.
x^{2}+\frac{6}{5}x=\frac{0}{\frac{5}{3}}
2 ni \frac{5}{3} ga bo'lish 2 ga k'paytirish \frac{5}{3} ga qaytarish.
x^{2}+\frac{6}{5}x=0
0 ni \frac{5}{3} ga bo'lish 0 ga k'paytirish \frac{5}{3} ga qaytarish.
x^{2}+\frac{6}{5}x+\left(\frac{3}{5}\right)^{2}=\left(\frac{3}{5}\right)^{2}
\frac{6}{5} ni bo‘lish, x shartining koeffitsienti, 2 ga \frac{3}{5} olish uchun. Keyin, \frac{3}{5} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}+\frac{6}{5}x+\frac{9}{25}=\frac{9}{25}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib \frac{3}{5} kvadratini chiqarish.
\left(x+\frac{3}{5}\right)^{2}=\frac{9}{25}
x^{2}+\frac{6}{5}x+\frac{9}{25} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x+\frac{3}{5}\right)^{2}}=\sqrt{\frac{9}{25}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x+\frac{3}{5}=\frac{3}{5} x+\frac{3}{5}=-\frac{3}{5}
Qisqartirish.
x=0 x=-\frac{6}{5}
Tenglamaning ikkala tarafidan \frac{3}{5} ni ayirish.
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