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\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{\left(2\sqrt{7}-2\sqrt{5}\right)\left(2\sqrt{7}+2\sqrt{5}\right)}
\frac{5}{2\sqrt{7}-2\sqrt{5}} maxrajini 2\sqrt{7}+2\sqrt{5} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{\left(2\sqrt{7}\right)^{2}-\left(-2\sqrt{5}\right)^{2}}
Hisoblang: \left(2\sqrt{7}-2\sqrt{5}\right)\left(2\sqrt{7}+2\sqrt{5}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{2^{2}\left(\sqrt{7}\right)^{2}-\left(-2\sqrt{5}\right)^{2}}
\left(2\sqrt{7}\right)^{2} ni kengaytirish.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{4\left(\sqrt{7}\right)^{2}-\left(-2\sqrt{5}\right)^{2}}
2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{4\times 7-\left(-2\sqrt{5}\right)^{2}}
\sqrt{7} kvadrati – 7.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{28-\left(-2\sqrt{5}\right)^{2}}
28 hosil qilish uchun 4 va 7 ni ko'paytirish.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{28-\left(-2\right)^{2}\left(\sqrt{5}\right)^{2}}
\left(-2\sqrt{5}\right)^{2} ni kengaytirish.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{28-4\left(\sqrt{5}\right)^{2}}
2 daraja ko‘rsatkichini -2 ga hisoblang va 4 ni qiymatni oling.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{28-4\times 5}
\sqrt{5} kvadrati – 5.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{28-20}
20 hosil qilish uchun 4 va 5 ni ko'paytirish.
\frac{5\left(2\sqrt{7}+2\sqrt{5}\right)}{8}
8 olish uchun 28 dan 20 ni ayirish.
\frac{10\sqrt{7}+10\sqrt{5}}{8}
5 ga 2\sqrt{7}+2\sqrt{5} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.