Baholash
7\sqrt{3}+13\approx 25,124355653
Baham ko'rish
Klipbordga nusxa olish
\frac{\left(5+\sqrt{3}\right)\left(2+\sqrt{3}\right)}{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}
\frac{5+\sqrt{3}}{2-\sqrt{3}} maxrajini 2+\sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(5+\sqrt{3}\right)\left(2+\sqrt{3}\right)}{2^{2}-\left(\sqrt{3}\right)^{2}}
Hisoblang: \left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(5+\sqrt{3}\right)\left(2+\sqrt{3}\right)}{4-3}
2 kvadratini chiqarish. \sqrt{3} kvadratini chiqarish.
\frac{\left(5+\sqrt{3}\right)\left(2+\sqrt{3}\right)}{1}
1 olish uchun 4 dan 3 ni ayirish.
\left(5+\sqrt{3}\right)\left(2+\sqrt{3}\right)
Har qanday son birga bo‘linganda, natija o‘zi chiqadi.
10+5\sqrt{3}+2\sqrt{3}+\left(\sqrt{3}\right)^{2}
5+\sqrt{3} ifodaning har bir elementini 2+\sqrt{3} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
10+7\sqrt{3}+\left(\sqrt{3}\right)^{2}
7\sqrt{3} ni olish uchun 5\sqrt{3} va 2\sqrt{3} ni birlashtirish.
10+7\sqrt{3}+3
\sqrt{3} kvadrati – 3.
13+7\sqrt{3}
13 olish uchun 10 va 3'ni qo'shing.
Misollar
Ikkilik tenglama
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometriya
4 \sin \theta \cos \theta = 2 \sin \theta
Chiziqli tenglama
y = 3x + 4
Arifmetik
699 * 533
Matritsa
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simli tenglama
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differensatsiya
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Oʻngga
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Chegaralar
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}