40/56x+(23y-10y-x)*40/74=203*40/1000 eching

$$\frac { 40 } { 56 } x + ( 23 y - 10 y - x ) \times \frac { 40 } { 74 } = 203 \times \frac { 40 } { 1000 }$$

x uchun yechish

$$x=-\frac{364y}{9}+\frac{52577}{1125}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{40}{56} ulushini 8 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{5}{7}x+\left(23y-10y-x\right)\times \frac{40}{74}=203\times \frac{40}{1000}$$

13y ni olish uchun 23y va -10y ni birlashtirish.

$$\frac{5}{7}x+\left(13y-x\right)\times \frac{40}{74}=203\times \frac{40}{1000}$$

\frac{40}{74} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{5}{7}x+\left(13y-x\right)\times \frac{20}{37}=203\times \frac{40}{1000}$$

13y-x ga \frac{20}{37} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{5}{7}x+\frac{260}{37}y-\frac{20}{37}x=203\times \frac{40}{1000}$$

\frac{45}{259}x ni olish uchun \frac{5}{7}x va -\frac{20}{37}x ni birlashtirish.

$$\frac{45}{259}x+\frac{260}{37}y=203\times \frac{40}{1000}$$

\frac{40}{1000} ulushini 40 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{45}{259}x+\frac{260}{37}y=203\times \frac{1}{25}$$

\frac{203}{25} hosil qilish uchun 203 va \frac{1}{25} ni ko'paytirish.

$$\frac{45}{259}x+\frac{260}{37}y=\frac{203}{25}$$

Ikkala tarafdan \frac{260}{37}y ni ayirish.

$$\frac{45}{259}x=\frac{203}{25}-\frac{260}{37}y$$

Tenglama standart shaklda.

$$\frac{45}{259}x=-\frac{260y}{37}+\frac{203}{25}$$

Tenglamaning ikki tarafini \frac{45}{259} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{45}{259}x}{\frac{45}{259}}=\frac{-\frac{260y}{37}+\frac{203}{25}}{\frac{45}{259}}$$

\frac{45}{259} ga bo'lish \frac{45}{259} ga ko'paytirishni bekor qiladi.

$$x=\frac{-\frac{260y}{37}+\frac{203}{25}}{\frac{45}{259}}$$

\frac{203}{25}-\frac{260y}{37} ni \frac{45}{259} ga bo'lish \frac{203}{25}-\frac{260y}{37} ga k'paytirish \frac{45}{259} ga qaytarish.

$$x=-\frac{364y}{9}+\frac{52577}{1125}$$

y uchun yechish

$$y=-\frac{9x}{364}+\frac{7511}{6500}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{40}{56} ulushini 8 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{5}{7}x+\left(23y-10y-x\right)\times \frac{40}{74}=203\times \frac{40}{1000}$$

13y ni olish uchun 23y va -10y ni birlashtirish.

$$\frac{5}{7}x+\left(13y-x\right)\times \frac{40}{74}=203\times \frac{40}{1000}$$

\frac{40}{74} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{5}{7}x+\left(13y-x\right)\times \frac{20}{37}=203\times \frac{40}{1000}$$

13y-x ga \frac{20}{37} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{5}{7}x+\frac{260}{37}y-\frac{20}{37}x=203\times \frac{40}{1000}$$

\frac{45}{259}x ni olish uchun \frac{5}{7}x va -\frac{20}{37}x ni birlashtirish.

$$\frac{45}{259}x+\frac{260}{37}y=203\times \frac{40}{1000}$$

\frac{40}{1000} ulushini 40 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{45}{259}x+\frac{260}{37}y=203\times \frac{1}{25}$$

\frac{203}{25} hosil qilish uchun 203 va \frac{1}{25} ni ko'paytirish.

$$\frac{45}{259}x+\frac{260}{37}y=\frac{203}{25}$$

Ikkala tarafdan \frac{45}{259}x ni ayirish.

$$\frac{260}{37}y=\frac{203}{25}-\frac{45}{259}x$$

Tenglama standart shaklda.

$$\frac{260}{37}y=-\frac{45x}{259}+\frac{203}{25}$$

Tenglamaning ikki tarafini \frac{260}{37} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{260}{37}y}{\frac{260}{37}}=\frac{-\frac{45x}{259}+\frac{203}{25}}{\frac{260}{37}}$$

\frac{260}{37} ga bo'lish \frac{260}{37} ga ko'paytirishni bekor qiladi.

$$y=\frac{-\frac{45x}{259}+\frac{203}{25}}{\frac{260}{37}}$$

\frac{203}{25}-\frac{45x}{259} ni \frac{260}{37} ga bo'lish \frac{203}{25}-\frac{45x}{259} ga k'paytirish \frac{260}{37} ga qaytarish.

$$y=-\frac{9x}{364}+\frac{7511}{6500}$$