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4x-2-x^{2}=2x-4
x qiymati 1 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-1 ga ko'paytirish.
4x-2-x^{2}-2x=-4
Ikkala tarafdan 2x ni ayirish.
2x-2-x^{2}=-4
2x ni olish uchun 4x va -2x ni birlashtirish.
2x-2-x^{2}+4=0
4 ni ikki tarafga qo’shing.
2x+2-x^{2}=0
2 olish uchun -2 va 4'ni qo'shing.
-x^{2}+2x+2=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-2±\sqrt{2^{2}-4\left(-1\right)\times 2}}{2\left(-1\right)}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 2 ni b va 2 ni c bilan almashtiring.
x=\frac{-2±\sqrt{4-4\left(-1\right)\times 2}}{2\left(-1\right)}
2 kvadratini chiqarish.
x=\frac{-2±\sqrt{4+4\times 2}}{2\left(-1\right)}
-4 ni -1 marotabaga ko'paytirish.
x=\frac{-2±\sqrt{4+8}}{2\left(-1\right)}
4 ni 2 marotabaga ko'paytirish.
x=\frac{-2±\sqrt{12}}{2\left(-1\right)}
4 ni 8 ga qo'shish.
x=\frac{-2±2\sqrt{3}}{2\left(-1\right)}
12 ning kvadrat ildizini chiqarish.
x=\frac{-2±2\sqrt{3}}{-2}
2 ni -1 marotabaga ko'paytirish.
x=\frac{2\sqrt{3}-2}{-2}
x=\frac{-2±2\sqrt{3}}{-2} tenglamasini yeching, bunda ± musbat. -2 ni 2\sqrt{3} ga qo'shish.
x=1-\sqrt{3}
-2+2\sqrt{3} ni -2 ga bo'lish.
x=\frac{-2\sqrt{3}-2}{-2}
x=\frac{-2±2\sqrt{3}}{-2} tenglamasini yeching, bunda ± manfiy. -2 dan 2\sqrt{3} ni ayirish.
x=\sqrt{3}+1
-2-2\sqrt{3} ni -2 ga bo'lish.
x=1-\sqrt{3} x=\sqrt{3}+1
Tenglama yechildi.
4x-2-x^{2}=2x-4
x qiymati 1 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini x-1 ga ko'paytirish.
4x-2-x^{2}-2x=-4
Ikkala tarafdan 2x ni ayirish.
2x-2-x^{2}=-4
2x ni olish uchun 4x va -2x ni birlashtirish.
2x-x^{2}=-4+2
2 ni ikki tarafga qo’shing.
2x-x^{2}=-2
-2 olish uchun -4 va 2'ni qo'shing.
-x^{2}+2x=-2
Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.
\frac{-x^{2}+2x}{-1}=-\frac{2}{-1}
Ikki tarafini -1 ga bo‘ling.
x^{2}+\frac{2}{-1}x=-\frac{2}{-1}
-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.
x^{2}-2x=-\frac{2}{-1}
2 ni -1 ga bo'lish.
x^{2}-2x=2
-2 ni -1 ga bo'lish.
x^{2}-2x+1=2+1
-2 ni bo‘lish, x shartining koeffitsienti, 2 ga -1 olish uchun. Keyin, -1 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}-2x+1=3
2 ni 1 ga qo'shish.
\left(x-1\right)^{2}=3
x^{2}-2x+1 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x-1\right)^{2}}=\sqrt{3}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x-1=\sqrt{3} x-1=-\sqrt{3}
Qisqartirish.
x=\sqrt{3}+1 x=1-\sqrt{3}
1 ni tenglamaning ikkala tarafiga qo'shish.