4x-16/x^2-8x+16=4/x-4 eching

$$\frac { 4 x - 16 } { x ^ { 2 } - 8 x + 16 } = \frac { 4 } { x - 4 }$$

x uchun yechish

$$x\neq 4$$

Yechim qadamlari

x qiymati 4 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini \left(x-4\right)^{2} ga, x^{2}-8x+16,x-4 ning eng kichik karralisiga ko‘paytiring.

$$4x-16=\left(x-4\right)\times 4$$

x-4 ga 4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x-16=4x-16$$

Ikkala tarafdan 4x ni ayirish.

$$4x-16-4x=-16$$

0 ni olish uchun 4x va -4x ni birlashtirish.

$$-16=-16$$

-16 va -16 ni taqqoslang.

$$\text{true}$$

Bu har qanday x uchun to‘g‘ri.

$$x\in \mathrm{R}$$

x qiymati 4 teng bo‘lmaydi.

$$x\in \mathrm{R}\setminus 4$$