4x-12+21-(x)+a^2+6x+9/a(a+3)(a-3) eching

$$\frac { 4 x - 12 + 21 - ( x ) + a ^ { 2 } + 6 x + 9 } { a ( a + 3 ) ( a - 3 ) }$$

Baholash

$$\frac{9x+a^{2}+18}{a\left(a^{2}-9\right)}$$

$$a\neq 0\text{ and }|a|\neq 3$$

Qisqa yechim qadamlari

9 olish uchun -12 va 21'ni qo'shing.

$$\frac{4x+9-x+a^{2}+6x+9}{a\left(a+3\right)\left(a-3\right)}$$

3x ni olish uchun 4x va -x ni birlashtirish.

$$\frac{3x+9+a^{2}+6x+9}{a\left(a+3\right)\left(a-3\right)}$$

9x ni olish uchun 3x va 6x ni birlashtirish.

$$\frac{9x+9+a^{2}+9}{a\left(a+3\right)\left(a-3\right)}$$

18 olish uchun 9 va 9'ni qo'shing.

$$\frac{9x+18+a^{2}}{a\left(a+3\right)\left(a-3\right)}$$

a ga a+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{9x+18+a^{2}}{\left(a^{2}+3a\right)\left(a-3\right)}$$

a^{2}+3a ga a-3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{9x+18+a^{2}}{a^{3}-9a}$$

Kengaytirish

$$\frac{9x+a^{2}+18}{a\left(a^{2}-9\right)}$$

$$a\neq 0\text{ and }|a|\neq 3$$

Qisqa yechim qadamlari

9 olish uchun -12 va 21'ni qo'shing.

$$\frac{4x+9-x+a^{2}+6x+9}{a\left(a+3\right)\left(a-3\right)}$$

3x ni olish uchun 4x va -x ni birlashtirish.

$$\frac{3x+9+a^{2}+6x+9}{a\left(a+3\right)\left(a-3\right)}$$

9x ni olish uchun 3x va 6x ni birlashtirish.

$$\frac{9x+9+a^{2}+9}{a\left(a+3\right)\left(a-3\right)}$$

18 olish uchun 9 va 9'ni qo'shing.

$$\frac{9x+18+a^{2}}{a\left(a+3\right)\left(a-3\right)}$$

a ga a+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{9x+18+a^{2}}{\left(a^{2}+3a\right)\left(a-3\right)}$$

a^{2}+3a ga a-3 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{9x+18+a^{2}}{a^{3}-9a}$$