4/40+y+16/40=31/40+6/40 eching

$$\frac { 4 } { 40 } + y + \frac { 16 } { 40 } = \frac { 31 } { 40 } + \frac { 6 } { 40 }$$

y uchun yechish

$$y=\frac{17}{40}=0,425$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\frac{4}{40} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{1}{10}+y+\frac{16}{40}=\frac{31}{40}+\frac{6}{40}$$

\frac{16}{40} ulushini 8 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{1}{10}+y+\frac{2}{5}=\frac{31}{40}+\frac{6}{40}$$

10 va 5 ning eng kichik umumiy karralisi 10 ga teng. \frac{1}{10} va \frac{2}{5} ni 10 maxraj bilan kasrlarga aylantirib oling.

$$\frac{1}{10}+y+\frac{4}{10}=\frac{31}{40}+\frac{6}{40}$$

\frac{1}{10} va \frac{4}{10} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{1+4}{10}+y=\frac{31}{40}+\frac{6}{40}$$

5 olish uchun 1 va 4'ni qo'shing.

$$\frac{5}{10}+y=\frac{31}{40}+\frac{6}{40}$$

\frac{5}{10} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{1}{2}+y=\frac{31}{40}+\frac{6}{40}$$

\frac{6}{40} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$\frac{1}{2}+y=\frac{31}{40}+\frac{3}{20}$$

40 va 20 ning eng kichik umumiy karralisi 40 ga teng. \frac{31}{40} va \frac{3}{20} ni 40 maxraj bilan kasrlarga aylantirib oling.

$$\frac{1}{2}+y=\frac{31}{40}+\frac{6}{40}$$

\frac{31}{40} va \frac{6}{40} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$\frac{1}{2}+y=\frac{31+6}{40}$$

37 olish uchun 31 va 6'ni qo'shing.

$$\frac{1}{2}+y=\frac{37}{40}$$

Ikkala tarafdan \frac{1}{2} ni ayirish.

$$y=\frac{37}{40}-\frac{1}{2}$$

40 va 2 ning eng kichik umumiy karralisi 40 ga teng. \frac{37}{40} va \frac{1}{2} ni 40 maxraj bilan kasrlarga aylantirib oling.

$$y=\frac{37}{40}-\frac{20}{40}$$

\frac{37}{40} va \frac{20}{40} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$y=\frac{37-20}{40}$$

17 olish uchun 37 dan 20 ni ayirish.

$$y=\frac{17}{40}$$