4/3+4/x-4=x+20/3x-12 eching

$$\frac { 4 } { 3 } + \frac { 4 } { x - 4 } = \frac { x + 20 } { 3 x - 12 }$$

x uchun yechish

$$x=8$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati 4 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 3\left(x-4\right) ga, 3,x-4,3x-12 ning eng kichik karralisiga ko‘paytiring.

$$3\left(x-4\right)\times \frac{4}{3}+3\times 4=x+20$$

3 ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\left(3x-12\right)\times \frac{4}{3}+3\times 4=x+20$$

3x-12 ga \frac{4}{3} ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x-16+3\times 4=x+20$$

12 hosil qilish uchun 3 va 4 ni ko'paytirish.

$$4x-16+12=x+20$$

-4 olish uchun -16 va 12'ni qo'shing.

$$4x-4=x+20$$

Ikkala tarafdan x ni ayirish.

$$4x-4-x=20$$

3x ni olish uchun 4x va -x ni birlashtirish.

$$3x-4=20$$

4 ni ikki tarafga qo’shing.

$$3x=20+4$$

24 olish uchun 20 va 4'ni qo'shing.

$$3x=24$$

Ikki tarafini 3 ga bo‘ling.

$$x=\frac{24}{3}$$

8 ni olish uchun 24 ni 3 ga bo‘ling.

$$x=8$$