Baholash
6\sqrt{2}+8-3\sqrt{6}-4\sqrt{3}\approx 2,208608916
Baham ko'rish
Klipbordga nusxa olish
\frac{\left(4+3\sqrt{2}\right)\left(2-\sqrt{3}\right)}{\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)}
\frac{4+3\sqrt{2}}{2+\sqrt{3}} maxrajini 2-\sqrt{3} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(4+3\sqrt{2}\right)\left(2-\sqrt{3}\right)}{2^{2}-\left(\sqrt{3}\right)^{2}}
Hisoblang: \left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(4+3\sqrt{2}\right)\left(2-\sqrt{3}\right)}{4-3}
2 kvadratini chiqarish. \sqrt{3} kvadratini chiqarish.
\frac{\left(4+3\sqrt{2}\right)\left(2-\sqrt{3}\right)}{1}
1 olish uchun 4 dan 3 ni ayirish.
\left(4+3\sqrt{2}\right)\left(2-\sqrt{3}\right)
Har qanday son birga bo‘linganda, natija o‘zi chiqadi.
8-4\sqrt{3}+6\sqrt{2}-3\sqrt{3}\sqrt{2}
4+3\sqrt{2} ifodaning har bir elementini 2-\sqrt{3} ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
8-4\sqrt{3}+6\sqrt{2}-3\sqrt{6}
\sqrt{3} va \sqrt{2} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.
Misollar
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Matritsa
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simli tenglama
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Differensatsiya
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Oʻngga
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Chegaralar
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