324/n^3(n(2n+1)(n+1)/6) eching

$$\frac { 324 } { n ^ { 3 } } ( \frac { n ( 2 n + 1 ) ( n + 1 ) } { 6 } )$$

Baholash

$$108+\frac{162}{n}+\frac{54}{n^{2}}$$

Qisqa yechim qadamlari

n ga 2n+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{324}{n^{3}}\times \frac{\left(2n^{2}+n\right)\left(n+1\right)}{6}$$

2n^{2}+n ga n+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{324}{n^{3}}\times \frac{2n^{3}+3n^{2}+n}{6}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{324}{n^{3}} ni \frac{2n^{3}+3n^{2}+n}{6} ga ko‘paytiring.

$$\frac{324\left(2n^{3}+3n^{2}+n\right)}{n^{3}\times 6}$$

Surat va maxrajdagi ikkala 6 ni qisqartiring.

$$\frac{54\left(2n^{3}+3n^{2}+n\right)}{n^{3}}$$

Hali faktorlanmagan ifodalarni faktorlang.

$$\frac{54n\left(n+1\right)\left(2n+1\right)}{n^{3}}$$

Surat va maxrajdagi ikkala n ni qisqartiring.

$$\frac{54\left(n+1\right)\left(2n+1\right)}{n^{2}}$$

Ifodani kengaytiring.

$$\frac{108n^{2}+162n+54}{n^{2}}$$

Kengaytirish

$$108+\frac{162}{n}+\frac{54}{n^{2}}$$

Qisqa yechim qadamlari

n ga 2n+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{324}{n^{3}}\times \frac{\left(2n^{2}+n\right)\left(n+1\right)}{6}$$

2n^{2}+n ga n+1 ni ko‘paytirish orqali distributiv xususiyatdan foydalaning va ifoda sifatida birlashtiring.

$$\frac{324}{n^{3}}\times \frac{2n^{3}+3n^{2}+n}{6}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{324}{n^{3}} ni \frac{2n^{3}+3n^{2}+n}{6} ga ko‘paytiring.

$$\frac{324\left(2n^{3}+3n^{2}+n\right)}{n^{3}\times 6}$$

Surat va maxrajdagi ikkala 6 ni qisqartiring.

$$\frac{54\left(2n^{3}+3n^{2}+n\right)}{n^{3}}$$

Hali faktorlanmagan ifodalarni faktorlang.

$$\frac{54n\left(n+1\right)\left(2n+1\right)}{n^{3}}$$

Surat va maxrajdagi ikkala n ni qisqartiring.

$$\frac{54\left(n+1\right)\left(2n+1\right)}{n^{2}}$$

Ifodani kengaytiring.

$$\frac{108n^{2}+162n+54}{n^{2}}$$