3z/m+n/b=f eching

$$\frac { 3 z } { m } + \frac { n } { b } = f$$

b uchun yechish

$$\left\{\begin{matrix}b=-\frac{mn}{3z-fm}\text{, }&m\neq 0\text{ and }n\neq 0\text{ and }z\neq \frac{fm}{3}\\b\neq 0\text{, }&z=\frac{fm}{3}\text{ and }n=0\text{ and }m\neq 0\end{matrix}\right,$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

b qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini bm ga, m,b ning eng kichik karralisiga ko‘paytiring.

$$b\times 3z+mn=fbm$$

Ikkala tarafdan fbm ni ayirish.

$$b\times 3z+mn-fbm=0$$

Ikkala tarafdan mn ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$b\times 3z-fbm=-mn$$

b'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(3z-fm\right)b=-mn$$

Ikki tarafini 3z-mf ga bo‘ling.

$$\frac{\left(3z-fm\right)b}{3z-fm}=-\frac{mn}{3z-fm}$$

3z-mf ga bo'lish 3z-mf ga ko'paytirishni bekor qiladi.

$$b=-\frac{mn}{3z-fm}$$

b qiymati 0 teng bo‘lmaydi.

$$b=-\frac{mn}{3z-fm}\text{, }b\neq 0$$

f uchun yechish

$$f=\frac{3bz+mn}{bm}$$

$$m\neq 0\text{ and }b\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini bm ga, m,b ning eng kichik karralisiga ko‘paytiring.

$$b\times 3z+mn=fbm$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$fbm=b\times 3z+mn$$

Tenglama standart shaklda.

$$bmf=3bz+mn$$

Ikki tarafini bm ga bo‘ling.

$$\frac{bmf}{bm}=\frac{3bz+mn}{bm}$$

bm ga bo'lish bm ga ko'paytirishni bekor qiladi.

$$f=\frac{3bz+mn}{bm}$$

3zb+nm ni bm ga bo'lish.

$$f=\frac{n}{b}+\frac{3z}{m}$$