y uchun yechish
y=-\frac{1}{3}\approx -0,333333333
y=2
Grafik
Baham ko'rish
Klipbordga nusxa olish
\frac{3}{5}y^{2}-\frac{2}{5}=y
\frac{3}{5}y^{2}-\frac{2}{5} natijani olish uchun 3y^{2}-2 ning har bir ifodasini 5 ga bo‘ling.
\frac{3}{5}y^{2}-\frac{2}{5}-y=0
Ikkala tarafdan y ni ayirish.
\frac{3}{5}y^{2}-y-\frac{2}{5}=0
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
y=\frac{-\left(-1\right)±\sqrt{1-4\times \frac{3}{5}\left(-\frac{2}{5}\right)}}{2\times \frac{3}{5}}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} \frac{3}{5} ni a, -1 ni b va -\frac{2}{5} ni c bilan almashtiring.
y=\frac{-\left(-1\right)±\sqrt{1-\frac{12}{5}\left(-\frac{2}{5}\right)}}{2\times \frac{3}{5}}
-4 ni \frac{3}{5} marotabaga ko'paytirish.
y=\frac{-\left(-1\right)±\sqrt{1+\frac{24}{25}}}{2\times \frac{3}{5}}
Raqamlash sonlarini va maxraj sonlariga ko'paytirish orqali -\frac{12}{5} ni -\frac{2}{5} ga ko'paytirish. So'ngra kasrni imkoni boricha eng kam a'zoga qisqartiring.
y=\frac{-\left(-1\right)±\sqrt{\frac{49}{25}}}{2\times \frac{3}{5}}
1 ni \frac{24}{25} ga qo'shish.
y=\frac{-\left(-1\right)±\frac{7}{5}}{2\times \frac{3}{5}}
\frac{49}{25} ning kvadrat ildizini chiqarish.
y=\frac{1±\frac{7}{5}}{2\times \frac{3}{5}}
-1 ning teskarisi 1 ga teng.
y=\frac{1±\frac{7}{5}}{\frac{6}{5}}
2 ni \frac{3}{5} marotabaga ko'paytirish.
y=\frac{\frac{12}{5}}{\frac{6}{5}}
y=\frac{1±\frac{7}{5}}{\frac{6}{5}} tenglamasini yeching, bunda ± musbat. 1 ni \frac{7}{5} ga qo'shish.
y=2
\frac{12}{5} ni \frac{6}{5} ga bo'lish \frac{12}{5} ga k'paytirish \frac{6}{5} ga qaytarish.
y=-\frac{\frac{2}{5}}{\frac{6}{5}}
y=\frac{1±\frac{7}{5}}{\frac{6}{5}} tenglamasini yeching, bunda ± manfiy. 1 dan \frac{7}{5} ni ayirish.
y=-\frac{1}{3}
-\frac{2}{5} ni \frac{6}{5} ga bo'lish -\frac{2}{5} ga k'paytirish \frac{6}{5} ga qaytarish.
y=2 y=-\frac{1}{3}
Tenglama yechildi.
\frac{3}{5}y^{2}-\frac{2}{5}=y
\frac{3}{5}y^{2}-\frac{2}{5} natijani olish uchun 3y^{2}-2 ning har bir ifodasini 5 ga bo‘ling.
\frac{3}{5}y^{2}-\frac{2}{5}-y=0
Ikkala tarafdan y ni ayirish.
\frac{3}{5}y^{2}-y=\frac{2}{5}
\frac{2}{5} ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
\frac{\frac{3}{5}y^{2}-y}{\frac{3}{5}}=\frac{\frac{2}{5}}{\frac{3}{5}}
Tenglamaning ikki tarafini \frac{3}{5} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.
y^{2}+\left(-\frac{1}{\frac{3}{5}}\right)y=\frac{\frac{2}{5}}{\frac{3}{5}}
\frac{3}{5} ga bo'lish \frac{3}{5} ga ko'paytirishni bekor qiladi.
y^{2}-\frac{5}{3}y=\frac{\frac{2}{5}}{\frac{3}{5}}
-1 ni \frac{3}{5} ga bo'lish -1 ga k'paytirish \frac{3}{5} ga qaytarish.
y^{2}-\frac{5}{3}y=\frac{2}{3}
\frac{2}{5} ni \frac{3}{5} ga bo'lish \frac{2}{5} ga k'paytirish \frac{3}{5} ga qaytarish.
y^{2}-\frac{5}{3}y+\left(-\frac{5}{6}\right)^{2}=\frac{2}{3}+\left(-\frac{5}{6}\right)^{2}
-\frac{5}{3} ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{5}{6} olish uchun. Keyin, -\frac{5}{6} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
y^{2}-\frac{5}{3}y+\frac{25}{36}=\frac{2}{3}+\frac{25}{36}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{5}{6} kvadratini chiqarish.
y^{2}-\frac{5}{3}y+\frac{25}{36}=\frac{49}{36}
Umumiy maxrajni topib va hisoblovchini qo'shish orqali \frac{2}{3} ni \frac{25}{36} ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.
\left(y-\frac{5}{6}\right)^{2}=\frac{49}{36}
y^{2}-\frac{5}{3}y+\frac{25}{36} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(y-\frac{5}{6}\right)^{2}}=\sqrt{\frac{49}{36}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
y-\frac{5}{6}=\frac{7}{6} y-\frac{5}{6}=-\frac{7}{6}
Qisqartirish.
y=2 y=-\frac{1}{3}
\frac{5}{6} ni tenglamaning ikkala tarafiga qo'shish.
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