3/8-a+3/4leqa-1/2 eching

$$\frac { 3 } { 8 } - \frac { a + 3 } { 4 } \leq \frac { a - 1 } { 2 }$$

a uchun yechish

$$a\geq \frac{1}{6}$$

Yechim qadamlari

Tenglamaning ikkala tarafini 8 ga, 8,4,2 ning eng kichik karralisiga ko‘paytiring. 8 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$3-2\left(a+3\right)\leq 4\left(a-1\right)$$

-2 ga a+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3-2a-6\leq 4\left(a-1\right)$$

-3 olish uchun 3 dan 6 ni ayirish.

$$-3-2a\leq 4\left(a-1\right)$$

4 ga a-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$-3-2a\leq 4a-4$$

Ikkala tarafdan 4a ni ayirish.

$$-3-2a-4a\leq -4$$

-6a ni olish uchun -2a va -4a ni birlashtirish.

$$-3-6a\leq -4$$

3 ni ikki tarafga qo’shing.

$$-6a\leq -4+3$$

-1 olish uchun -4 va 3'ni qo'shing.

$$-6a\leq -1$$

Ikki tarafini -6 ga bo‘ling. -6 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$a\geq \frac{-1}{-6}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-1}{-6} kasrini \frac{1}{6} ga soddalashtirish mumkin.

$$a\geq \frac{1}{6}$$