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\frac{3}{5}+\frac{25}{7}\left(-\frac{1}{4}\right)-\frac{5}{12}
\frac{3}{12} ulushini 3 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{3}{5}+\frac{25\left(-1\right)}{7\times 4}-\frac{5}{12}
Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{25}{7} ni -\frac{1}{4} ga ko‘paytiring.
\frac{3}{5}+\frac{-25}{28}-\frac{5}{12}
\frac{25\left(-1\right)}{7\times 4} kasridagi ko‘paytirishlarni bajaring.
\frac{3}{5}-\frac{25}{28}-\frac{5}{12}
\frac{-25}{28} kasri manfiy belgini olib tashlash bilan -\frac{25}{28} sifatida qayta yozilishi mumkin.
\frac{84}{140}-\frac{125}{140}-\frac{5}{12}
5 va 28 ning eng kichik umumiy karralisi 140 ga teng. \frac{3}{5} va \frac{25}{28} ni 140 maxraj bilan kasrlarga aylantirib oling.
\frac{84-125}{140}-\frac{5}{12}
\frac{84}{140} va \frac{125}{140} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.
-\frac{41}{140}-\frac{5}{12}
-41 olish uchun 84 dan 125 ni ayirish.
-\frac{123}{420}-\frac{175}{420}
140 va 12 ning eng kichik umumiy karralisi 420 ga teng. -\frac{41}{140} va \frac{5}{12} ni 420 maxraj bilan kasrlarga aylantirib oling.
\frac{-123-175}{420}
-\frac{123}{420} va \frac{175}{420} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.
\frac{-298}{420}
-298 olish uchun -123 dan 175 ni ayirish.
-\frac{149}{210}
\frac{-298}{420} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.