3/4(x+1)+x<6 eching

$$\frac { 3 } { 4 } ( x + 1 ) + x < 6$$

x uchun yechish

$$x<3$$

Yechim qadamlari

\frac{3}{4} ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$\frac{3}{4}x+\frac{3}{4}+x<6$$

\frac{7}{4}x ni olish uchun \frac{3}{4}x va x ni birlashtirish.

$$\frac{7}{4}x+\frac{3}{4}<6$$

Ikkala tarafdan \frac{3}{4} ni ayirish.

$$\frac{7}{4}x<6-\frac{3}{4}$$

6 ni \frac{24}{4} kasrga o‘giring.

$$\frac{7}{4}x<\frac{24}{4}-\frac{3}{4}$$

\frac{24}{4} va \frac{3}{4} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{7}{4}x<\frac{24-3}{4}$$

21 olish uchun 24 dan 3 ni ayirish.

$$\frac{7}{4}x<\frac{21}{4}$$

Ikki tarafini \frac{4}{7} va teskari kasri \frac{7}{4} ga ko‘paytiring. \frac{7}{4} musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x<\frac{21}{4}\times \frac{4}{7}$$

Suratni maxrajga va maxrajini suratga ko‘paytirish orqali \frac{21}{4} ni \frac{4}{7} ga ko‘paytiring.

$$x<\frac{21\times 4}{4\times 7}$$

Surat va maxrajdagi ikkala 4 ni qisqartiring.

$$x<\frac{21}{7}$$

3 ni olish uchun 21 ni 7 ga bo‘ling.

$$x<3$$