u uchun yechish
u=7
Baham ko'rish
Klipbordga nusxa olish
\frac{3}{4}u+\frac{3}{4}\left(-3\right)=\frac{1}{3}\left(2u-5\right)
\frac{3}{4} ga u-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
\frac{3}{4}u+\frac{3\left(-3\right)}{4}=\frac{1}{3}\left(2u-5\right)
\frac{3}{4}\left(-3\right) ni yagona kasrga aylantiring.
\frac{3}{4}u+\frac{-9}{4}=\frac{1}{3}\left(2u-5\right)
-9 hosil qilish uchun 3 va -3 ni ko'paytirish.
\frac{3}{4}u-\frac{9}{4}=\frac{1}{3}\left(2u-5\right)
\frac{-9}{4} kasri manfiy belgini olib tashlash bilan -\frac{9}{4} sifatida qayta yozilishi mumkin.
\frac{3}{4}u-\frac{9}{4}=\frac{1}{3}\times 2u+\frac{1}{3}\left(-5\right)
\frac{1}{3} ga 2u-5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u+\frac{1}{3}\left(-5\right)
\frac{2}{3} hosil qilish uchun \frac{1}{3} va 2 ni ko'paytirish.
\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u+\frac{-5}{3}
\frac{-5}{3} hosil qilish uchun \frac{1}{3} va -5 ni ko'paytirish.
\frac{3}{4}u-\frac{9}{4}=\frac{2}{3}u-\frac{5}{3}
\frac{-5}{3} kasri manfiy belgini olib tashlash bilan -\frac{5}{3} sifatida qayta yozilishi mumkin.
\frac{3}{4}u-\frac{9}{4}-\frac{2}{3}u=-\frac{5}{3}
Ikkala tarafdan \frac{2}{3}u ni ayirish.
\frac{1}{12}u-\frac{9}{4}=-\frac{5}{3}
\frac{1}{12}u ni olish uchun \frac{3}{4}u va -\frac{2}{3}u ni birlashtirish.
\frac{1}{12}u=-\frac{5}{3}+\frac{9}{4}
\frac{9}{4} ni ikki tarafga qo’shing.
\frac{1}{12}u=-\frac{20}{12}+\frac{27}{12}
3 va 4 ning eng kichik umumiy karralisi 12 ga teng. -\frac{5}{3} va \frac{9}{4} ni 12 maxraj bilan kasrlarga aylantirib oling.
\frac{1}{12}u=\frac{-20+27}{12}
-\frac{20}{12} va \frac{27}{12} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.
\frac{1}{12}u=\frac{7}{12}
7 olish uchun -20 va 27'ni qo'shing.
u=\frac{7}{12}\times 12
Ikki tarafini 12 va teskari kasri \frac{1}{12} ga ko‘paytiring.
u=7
12 va 12 ni qisqartiring.
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