3/4=39t+2/5x-1 eching

$$\frac { 3 } { 4 } = \frac { 39 t + 2 } { 5 x - 1 }$$

t uchun yechish

$$t=\frac{5x}{52}-\frac{11}{156}$$

$$x\neq \frac{1}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 4\left(5x-1\right) ga, 4,5x-1 ning eng kichik karralisiga ko‘paytiring.

$$3\left(5x-1\right)=4\left(39t+2\right)$$

3 ga 5x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$15x-3=4\left(39t+2\right)$$

4 ga 39t+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$15x-3=156t+8$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$156t+8=15x-3$$

Ikkala tarafdan 8 ni ayirish.

$$156t=15x-3-8$$

-11 olish uchun -3 dan 8 ni ayirish.

$$156t=15x-11$$

Ikki tarafini 156 ga bo‘ling.

$$\frac{156t}{156}=\frac{15x-11}{156}$$

156 ga bo'lish 156 ga ko'paytirishni bekor qiladi.

$$t=\frac{15x-11}{156}$$

15x-11 ni 156 ga bo'lish.

$$t=\frac{5x}{52}-\frac{11}{156}$$

x uchun yechish

$$x=\frac{52t}{5}+\frac{11}{15}$$

$$t\neq -\frac{2}{39}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati \frac{1}{5} teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 4\left(5x-1\right) ga, 4,5x-1 ning eng kichik karralisiga ko‘paytiring.

$$3\left(5x-1\right)=4\left(39t+2\right)$$

3 ga 5x-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$15x-3=4\left(39t+2\right)$$

4 ga 39t+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$15x-3=156t+8$$

3 ni ikki tarafga qo’shing.

$$15x=156t+8+3$$

11 olish uchun 8 va 3'ni qo'shing.

$$15x=156t+11$$

Ikki tarafini 15 ga bo‘ling.

$$\frac{15x}{15}=\frac{156t+11}{15}$$

15 ga bo'lish 15 ga ko'paytirishni bekor qiladi.

$$x=\frac{156t+11}{15}$$

156t+11 ni 15 ga bo'lish.

$$x=\frac{52t}{5}+\frac{11}{15}$$

x qiymati \frac{1}{5} teng bo‘lmaydi.

$$x=\frac{52t}{5}+\frac{11}{15}\text{, }x\neq \frac{1}{5}$$