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\frac{3\sqrt{3}-2}{2\sqrt{7}+1}\times 1
1 ni olish uchun 2\sqrt{7}-1 ni 2\sqrt{7}-1 ga bo‘ling.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right)}\times 1
\frac{3\sqrt{3}-2}{2\sqrt{7}+1} maxrajini 2\sqrt{7}-1 orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{\left(2\sqrt{7}\right)^{2}-1^{2}}\times 1
Hisoblang: \left(2\sqrt{7}+1\right)\left(2\sqrt{7}-1\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{2^{2}\left(\sqrt{7}\right)^{2}-1^{2}}\times 1
\left(2\sqrt{7}\right)^{2} ni kengaytirish.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\left(\sqrt{7}\right)^{2}-1^{2}}\times 1
2 daraja ko‘rsatkichini 2 ga hisoblang va 4 ni qiymatni oling.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{4\times 7-1^{2}}\times 1
\sqrt{7} kvadrati – 7.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1^{2}}\times 1
28 hosil qilish uchun 4 va 7 ni ko'paytirish.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{28-1}\times 1
2 daraja ko‘rsatkichini 1 ga hisoblang va 1 ni qiymatni oling.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}\times 1
27 olish uchun 28 dan 1 ni ayirish.
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}
\frac{\left(3\sqrt{3}-2\right)\left(2\sqrt{7}-1\right)}{27}\times 1 ni yagona kasrga aylantiring.
\frac{6\sqrt{3}\sqrt{7}-3\sqrt{3}-4\sqrt{7}+2}{27}
3\sqrt{3}-2 ifodaning har bir elementini 2\sqrt{7}-1 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.
\frac{6\sqrt{21}-3\sqrt{3}-4\sqrt{7}+2}{27}
\sqrt{3} va \sqrt{7} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.