25/2-(5-133/40-1/2)-11-13/40= eching

$$\frac { 25 } { 2 } - ( 5 - \frac { 133 } { 40 } - \frac { 1 } { 2 } ) - 11 - \frac { 13 } { 40 } =$$

Baholash

$$0$$

Yechim qadamlari

5 ni \frac{200}{40} kasrga o‘giring.

$$\frac{25}{2}-\left(\frac{200}{40}-\frac{133}{40}-\frac{1}{2}\right)-11-\frac{13}{40}$$

\frac{200}{40} va \frac{133}{40} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{25}{2}-\left(\frac{200-133}{40}-\frac{1}{2}\right)-11-\frac{13}{40}$$

67 olish uchun 200 dan 133 ni ayirish.

$$\frac{25}{2}-\left(\frac{67}{40}-\frac{1}{2}\right)-11-\frac{13}{40}$$

40 va 2 ning eng kichik umumiy karralisi 40 ga teng. \frac{67}{40} va \frac{1}{2} ni 40 maxraj bilan kasrlarga aylantirib oling.

$$\frac{25}{2}-\left(\frac{67}{40}-\frac{20}{40}\right)-11-\frac{13}{40}$$

\frac{67}{40} va \frac{20}{40} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{25}{2}-\frac{67-20}{40}-11-\frac{13}{40}$$

47 olish uchun 67 dan 20 ni ayirish.

$$\frac{25}{2}-\frac{47}{40}-11-\frac{13}{40}$$

2 va 40 ning eng kichik umumiy karralisi 40 ga teng. \frac{25}{2} va \frac{47}{40} ni 40 maxraj bilan kasrlarga aylantirib oling.

$$\frac{500}{40}-\frac{47}{40}-11-\frac{13}{40}$$

\frac{500}{40} va \frac{47}{40} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{500-47}{40}-11-\frac{13}{40}$$

453 olish uchun 500 dan 47 ni ayirish.

$$\frac{453}{40}-11-\frac{13}{40}$$

11 ni \frac{440}{40} kasrga o‘giring.

$$\frac{453}{40}-\frac{440}{40}-\frac{13}{40}$$

\frac{453}{40} va \frac{440}{40} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$\frac{453-440}{40}-\frac{13}{40}$$

13 olish uchun 453 dan 440 ni ayirish.

$$\frac{13}{40}-\frac{13}{40}$$

0 olish uchun \frac{13}{40} dan \frac{13}{40} ni ayirish.

$$0$$

Omil

$$0$$