20/r+xsqrt{x}+x=22 eching

$$\frac { 20 } { r } + x \sqrt { x } + x = 22$$

r uchun yechish

$$r=-\frac{20}{x^{\frac{3}{2}}+x-22}$$

$$x\neq \frac{\sqrt[3]{66\sqrt{9735}+6337}+\sqrt[3]{6337-66\sqrt{9735}}+1}{3}\text{ and }x\geq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

r qiymati 0 teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini r ga ko'paytirish.

$$20+x\sqrt{x}r+rx=22r$$

Ikkala tarafdan 22r ni ayirish.

$$20+x\sqrt{x}r+rx-22r=0$$

Ikkala tarafdan 20 ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$x\sqrt{x}r+rx-22r=-20$$

r'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(x\sqrt{x}+x-22\right)r=-20$$

Tenglama standart shaklda.

$$\left(\sqrt{x}x+x-22\right)r=-20$$

Ikki tarafini x\sqrt{x}+x-22 ga bo‘ling.

$$\frac{\left(\sqrt{x}x+x-22\right)r}{\sqrt{x}x+x-22}=-\frac{20}{\sqrt{x}x+x-22}$$

x\sqrt{x}+x-22 ga bo'lish x\sqrt{x}+x-22 ga ko'paytirishni bekor qiladi.

$$r=-\frac{20}{\sqrt{x}x+x-22}$$

-20 ni x\sqrt{x}+x-22 ga bo'lish.

$$r=-\frac{20}{x^{\frac{3}{2}}+x-22}$$

r qiymati 0 teng bo‘lmaydi.

$$r=-\frac{20}{x^{\frac{3}{2}}+x-22}\text{, }r\neq 0$$