2x-(7-5x)/9x-(3+4x)=7/6f eching

$$\frac { 2 x - ( 7 - 5 x ) } { 9 x - ( 3 + 4 x ) } = \frac { 7 } { 6 } f$$

f uchun yechish

$$f=-\frac{6\left(x-1\right)}{3-5x}$$

$$x\neq \frac{3}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 6\left(5x-3\right) ga, 9x-\left(3+4x\right),6 ning eng kichik karralisiga ko‘paytiring.

$$6\left(2x-\left(7-5x\right)\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

7-5x teskarisini topish uchun har birining teskarisini toping.

$$6\left(2x-7+5x\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

7x ni olish uchun 2x va 5x ni birlashtirish.

$$6\left(7x-7\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

6 ga 7x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$42x-42=\frac{7}{6}f\times 6\left(5x-3\right)$$

7 hosil qilish uchun \frac{7}{6} va 6 ni ko'paytirish.

$$42x-42=7f\left(5x-3\right)$$

7f ga 5x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$42x-42=35xf-21f$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$35xf-21f=42x-42$$

f'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(35x-21\right)f=42x-42$$

Ikki tarafini 35x-21 ga bo‘ling.

$$\frac{\left(35x-21\right)f}{35x-21}=\frac{42x-42}{35x-21}$$

35x-21 ga bo'lish 35x-21 ga ko'paytirishni bekor qiladi.

$$f=\frac{42x-42}{35x-21}$$

-42+42x ni 35x-21 ga bo'lish.

$$f=\frac{6\left(x-1\right)}{5x-3}$$

x uchun yechish

$$x=-\frac{3\left(f-2\right)}{6-5f}$$

$$f\neq \frac{6}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

x qiymati \frac{3}{5} teng bo‘lmaydi, chunki nolga bo‘lish mumkin emas. Tenglamaning ikkala tarafini 6\left(5x-3\right) ga, 9x-\left(3+4x\right),6 ning eng kichik karralisiga ko‘paytiring.

$$6\left(2x-\left(7-5x\right)\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

7-5x teskarisini topish uchun har birining teskarisini toping.

$$6\left(2x-7+5x\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

7x ni olish uchun 2x va 5x ni birlashtirish.

$$6\left(7x-7\right)=\frac{7}{6}f\times 6\left(5x-3\right)$$

6 ga 7x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$42x-42=\frac{7}{6}f\times 6\left(5x-3\right)$$

7 hosil qilish uchun \frac{7}{6} va 6 ni ko'paytirish.

$$42x-42=7f\left(5x-3\right)$$

7f ga 5x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$42x-42=35fx-21f$$

Ikkala tarafdan 35fx ni ayirish.

$$42x-42-35fx=-21f$$

42 ni ikki tarafga qo’shing.

$$42x-35fx=-21f+42$$

x'ga ega bo'lgan barcha shartlarni birlashtirish.

$$\left(42-35f\right)x=-21f+42$$

Tenglama standart shaklda.

$$\left(42-35f\right)x=42-21f$$

Ikki tarafini 42-35f ga bo‘ling.

$$\frac{\left(42-35f\right)x}{42-35f}=\frac{42-21f}{42-35f}$$

42-35f ga bo'lish 42-35f ga ko'paytirishni bekor qiladi.

$$x=\frac{42-21f}{42-35f}$$

-21f+42 ni 42-35f ga bo'lish.

$$x=\frac{3\left(2-f\right)}{6-5f}$$

x qiymati \frac{3}{5} teng bo‘lmaydi.

$$x=\frac{3\left(2-f\right)}{6-5f}\text{, }x\neq \frac{3}{5}$$